Answer:
16
Step-by-step explanation:
Substitute 3 for n,
6(3) - 2
then multiply
18 - 2
then subtract
16
Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
If the roots of the equation f(x)=0 are -4,-1, 2 and 5, then binomials (x+4), (x+1), (x-2) and (x-5) are factors of needed polynomial.
Thus, the polynomial will have form
where a is real coefficient (positive or negative). This polynomial has degree 4 as needed.
The form of the graph depends on the sign of coefficient a. Attached diagrams show two different cases of possible forms of graphs (first one for positive coefficient a, second one for negative coefficient a).
Step-by-step explanation:
Given equations:
y = x² + 3x - 29 ------ (i)
y = 2x - 9 ---------------- (ii)
Now to solve this problem, we must determine the value of x and y;
Equate equations 1 and 2;
x² + 3x - 29 = 2x - 9
x² + 3x - 2x - 29 + 9 = 0
x² + x - 20 = 0
x² + 5x - 4x - 20 = 0
x(x + 5 ) - 4(x + 5) = 0
(x - 4) (x+ 5) = 0
x - 4 = 0 or x + 5 = 0
x = 4 or x = -5;
So; solve for y now;
y = 2x - 9
input x = 4 or x = -5;
y = 2(4) - 9 or y = 2(-5) - 9
y = -1 or y = -19
