\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x2]=⎣⎢⎢⎢⎢⎡2323√(432by+√(−6912+41472by+103680by2+55296by3))−1+i√3+2by+(−2i)√3by+3√224−3√(432by+√(−6912+41472by+103680by2+55296by3))+(24−1i)√33√(432by+√(−6912+41472by+103680by2+55296by3))⎦⎥⎥⎥⎥⎤
totally answer.
Answer:
At least 39200 students.
Step-by-step explanation:
Given that there are 196 countries in the world, and each country would have at least 200 students in a university.
For each country to have at least 200 students in the university, then;
Number of students enrolled in the university = number of required students x number of countries
= 200 x 196
= 39200
At least, 39200 students must be enrolled in the university. Provided that the admission procedures are conditioned for the purpose.
Answer:
A is spanned by vector.
Step-by-step explanation:
The null space of matrix is set of all solutions to matrix. The linearly independent vectors forms subset which are spanned and forms the null space. The null space of vector can be found by reducing its echelon. The non zero rows formed are the null spaces of matrix.
Answer:
csc^2x
Step-by-step explanation:
It's a trig identity where 1+cot^2x = csc^2x
Answer:
18
Step-by-step explanation:
(-2)+(5 + 5)2
(-2)+(10)2
(-2)+20
-2+20=18
