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3 years ago

Which segment is an altitude of triangle IGH?

Mathematics

1 answer:

e-lub [12.9K]3 years ago

3 0

I know my math and your answer is going to be A.

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The graph of f is given in the figure to the right. Let A(x)equals=Integral from 0 to x f left parenthesis t right parenthesis

Tpy6a [65]

Answer:

$A(4)=-4\pi$

$A(8)=-4\pi +8$

$A(12)=-4\pi +16$

$A(14)=-4\pi +15$

Step-by-step explanation:

we are given

$A(x)=\int\limits^x_0 f{x} \, dx$

Calculation of A(4):

we can plug x=4

$A(4)=\int\limits^4_0 f{x} \, dx$

Since, this curve is below x-axis

so, the value of integral must be negative

and it is quarter of circle

so, we can find area of quarter circle

radius =4

$A(4)=-\frac{1}{4}\times \pi \times (4)^2$

$A(4)=-4\pi$

Calculation of A(8):

we can plug x=8

$A(8)=\int\limits^8_0 f{x} \, dx$

we can break into two parts

$A(8)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx$

now, we can find area and then combine them

$A(8)=-4\pi +\frac{1}{2}\times 4\times 4$

$A(8)=-4\pi +8$

Calculation of A(12):

we can plug x=12

$A(12)=\int\limits^12_0 f{x} \, dx$

we can break into two parts

$A(12)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx$

now, we can find area and then combine them

$A(12)=-4\pi +\frac{1}{2}\times 8\times 4$

$A(12)=-4\pi +16$

Calculation of A(14):

we can plug x=14

$A(14)=\int\limits^14_0 f{x} \, dx$

we can break into two parts

$A(14)=\int\limits^4_0 f{x} \, dx+\int\limits^8_4 f{x} \, dx+\int\limits^12_8 f{x} \, dx+\int\limits^14_12 f{x} \, dx$

now, we can find area and then combine them

$A(14)=-4\pi +\frac{1}{2}\times 8\times 4-\frac{1}{2}\times 1\times 2$

$A(14)=-4\pi +16-1$

$A(14)=-4\pi +15$

8 0

3 years ago

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 73' Building A is 30 feet away, and b

wlad13 [49]

Answer:

Building B, it is around 16 35 feet taller than building A ( C )

Step-by-step explanation:

<u>Calculating the height of Building A </u>

Height = opposite ( ? )

∅ = 73°

base/adjacent = 30 ft

∴ Height = Tan 73° * base

= 3.2709 * 30 = 98.127 ft

<u>Calculating the height of building B </u>

∅ = 73°

base/adjacent = 35 ft

∴ height = Tan 73° * base

= 3.2709 * 35 = 114.4815

Therefore we can say Building B is Taller by approximately 16.35 feet

7 0

2 years ago

4. Trazá y responde: Juan dibujó un ángulo de 150° y le trazó su bisectriz. Le quedaron dos ángulos, uno

Pachacha [2.7K]

Answer:

no, no esta bien. la bisectriz es la mitad de 150°, entonces seria 75° y 75°

Step-by-step explanation:

4 0

2 years ago

Help me plz !!!!!!!!!!

kiruha [24]

Answer:

The answer is b. 72.3cm

Step-by-step explanation:

11.5cm is the radius

To find the circumference multiply the radius by 2 then multiply it again by 3.14

3.14 is the beginning of pi.

e.g - 2 × 3.14 x 11.5

5 0

3 years ago

Read 2 more answers

Which shows the equation below written in the form ax^2+bx+c=0

Elza [17]

Answer:

Step-by-step explanation:

$x^{2} + 8x + 10 - 3 = 0\\x^{2} + 8x + 7$

6 0

3 years ago