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Vladimir79 [104]
3 years ago
11

Algebra 2 questions

Mathematics
2 answers:
Andru [333]3 years ago
5 0

Answer:

-9/22

Step-by-step explanation:

Cross multiply 3x+1 and x-5 to get 3x^2-14x-5

Cross multiply 3x+2 and x+2 to get 3x^2+8x+4

3x^2-14x-5=3x^2+8x+4

-14x-5=8x+4

-22x=9

x=-9/22

Juliette [100K]3 years ago
3 0
The answer would -9/22
Make sure you cross multiply
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Find the value of x in the triangle. Please show work. Help
Assoli18 [71]

there is no triangle drawn

4 0
3 years ago
Write an equivalent expression of -2(1.5h+5)-4(-0.5+3h) without parenthesis
ryzh [129]

The equivalent expression to given expression is: -15h-8

Step-by-step explanation:

We can simplify the given expression to find an equivalent expression.

Given expression is:

-2(1.5h+5)-4(-0.5+3h)

So by using distributive property

=-3h-10+2-12h\\=-15h-8

Hence,

The equivalent expression to given expression is: -15h-8

Keywords: Equivalent expressions, Polynomials

Learn more about polynomials at:

  • brainly.com/question/10552347
  • brainly.com/question/10570041

#LearnwithBrainly

8 0
2 years ago
a function is shown below: f(x) = (0.93)x what does the function represent? (5 points) exponential growth of 7% exponential deca
zimovet [89]
Exponential decay of 7%
3 0
3 years ago
Read 2 more answers
An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de
Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have:

P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have

P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453

The sum of the probabilities is

P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981

8 0
3 years ago
This is the homework question (Please see picture). If my X and Y's are correct how do I graph it?
Nataliya [291]

Answer:

to graph it. make a horizontal line for the x axis and a vertical line for the y axis and place your coordinate points were the are supposed to be and label them.

Step-by-step explanation:

  • Make the y and x axis.
  • label the coordinate points.
  • Example:

The coordinate points(3,7) means that 3 would be on the horizontal line and 7 would be on the vertical line meaning the coordinate point(3,7) would be located were the two numbers meet.

5 0
2 years ago
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