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Vladimir79 [104]
3 years ago
11

Algebra 2 questions

Mathematics
2 answers:
Andru [333]3 years ago
5 0

Answer:

-9/22

Step-by-step explanation:

Cross multiply 3x+1 and x-5 to get 3x^2-14x-5

Cross multiply 3x+2 and x+2 to get 3x^2+8x+4

3x^2-14x-5=3x^2+8x+4

-14x-5=8x+4

-22x=9

x=-9/22

Juliette [100K]3 years ago
3 0
The answer would -9/22
Make sure you cross multiply
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You buy 11 bagels with a $20 bill. How much change do you receive?
tangare [24]

Answer:

You would receive $13.75

Step-by-step explanation: What i did was divided 7.50 by 6 so it would give me the price of 1 bagel(1.25).I subtracted 11 and 6 which would give me 5 so I know how much I need to calculate with the discount. Then I multiplyed 5 times 1.25 (6.25) so I could get the price for 5 bagels. After I added 7.50 and 6.25 which would give you your answer of $13.75.

I hope this helps and makes sense to you. Please mark brainlist!

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Help ASAP plzzzz!!!! T^T
forsale [732]

Answer:

52.8

Step-by-step explanation:

3x5 =15 × 3 =45

1.5 x 2.6 = 3.9 x 2 =7.8

Combine

4 0
2 years ago
Which statements represent the relationship between y=2^x and y=log2 x?
laila [671]
Y = 2^x and y = log₂x

Exponents and logs (to the same base = 2) are inverses of each other.
All inverse functions are symmetric about line y = x

y = log₂x is NOT the logarithmic form of y = 2^x
The logarithmic form of y = 2^x is x = log₂y (NOT y = log₂x)

Answer: A, C
3 0
3 years ago
Can y’all help me please
matrenka [14]

Answer:

w = 5

Step-by-step explanation:

The perimeter of a rectangle is given by

P = 2(l+w)

28 = 2(2w-1 + w)

Combine like terms

28 =2(3w-1)

Divide each side by 2

28/2 = 2/2(3w-1)

14 = 3w-1

Add 1 to each side

14+1 = 3w-1+1

15 = 3w

Divide each side by 3

15/3 =3w/3

5 =w

8 0
3 years ago
Plz with steps .. it's very hard can anyone plz
liubo4ka [24]

Answer:

Step-by-step explanation:

\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a}  \qquad  f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a}  \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}}  }{\dfrac{1}{2\sqrt{x}} }\\\\

\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}  =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\

7 0
2 years ago
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