Answer:
m<SQP=124°
Step-by-step explanation:
Hi there!
We're given ΔQRS, the measure of <R (90°), and the measure of <S (34°)
we need to find m<SQP (given as x+72°)
exterior angle theorem is a theorem that states that an exterior angle (an angle on the OUTSIDE of a shape) is equal to the sum of the two remote interior angles (the angle OUTSIDE of a shape will be equal to the sum of 2 angles that are OPPOSITE to that angle).
that means that m<SQP=m<R+m<S (Exterior angle theorem)
substitute the known values into the equation
x+72°=90°+34° (substitution)
combine like terms on both sides
x+72°=124° (algebra)
subtract 72 from both sides
x=52° (algebra)
however, that's just the value of x. Because m<SQP is x+72°, add 52 and 72 together to get the value of m<SQP
m<SQP=x+72°=52°+72°=124° (substitution, algebra)
Hope this helps!
Answer:
Candace has $57.5 and Amar has $37.5.
Step-by-step explanation:
x+(x+20)=z
x+20=y
x+y=z
--------------
2x+20=95
2x=95-20
2x=75
x=75/2
x=37.5
37.5+20=y=57.5
You first have to plug in your given numbers to the equation.
d= rt
d=(52)4.5
Then you solve
52*4.5 = 234
So, your distance or d=234
