Answer:
2.76 (full answer) 2.7617e-6
Explanation:
Answer:
The water in the hydrate (referred to as "water of hydration") can be removed by heating the hydrate. When all hydrating water is removed, the material is said to be anhydrous and is referred to as an anhydrate.
Explanation:
Answer:
The answer to your question is 0.64 M
Explanation:
Data
Sucrose C₁₂H₂₂O₁₁ mass = 7.633 g
volume = 25 ml
Molarity = ?
Process
1.- Calculate the molar weight of Sucrose
C₁₂H₂₂O₁₁ = (12 x 12) +(22 x 1) + (11 x 16)
= 144 + 22 + 176
= 342 g
2.- Calculate the moles of sucrose
342 g ------------------ 1 mol
7.633 g --------------- x
x = (7.633 x 1) / 342
x = 0.0223 moles
3.- Calculate the molarity
Molarity = moles / volume (L)
Molarity = 0.0223 / 0.035
Molarity = 0.64