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babunello [35]
3 years ago
11

How many alcohols and ethers share the molecular formula c2h6o?

Chemistry
2 answers:
Katen [24]3 years ago
8 0

Answer:

Alcohol :CH₃-CH₂-OH (ethanol)

Ether: H₃C-O-CH₃  (dimethyl ether)

Explanation:

Alcohols are compounds containing the hydroxyl or the -OH functional group i.e. R-OH where R is an alkyl or aryl group

Ethers are compounds with a general structure, R-O-R' where R and R' are once again either alkyl or aryl groups.

The given compound has a molecular formula: C₂H₆O

Structure with 'alcohol' -OH functional group

CH₃-CH₂-OH ------- ethanol

Structure with ether functionality:

H₃C-O-CH₃     ---------dimethyl ether

Nadya [2.5K]3 years ago
4 0

Answer is: there are two compounds with molecular formula C₂H₆O, one alcohol and one ethar.

Alcohol with molecular formula C₂H₆O is ethanol or ethyl alcohol (C₂H₅OH).

Ethanol is a volatile, flammable, colorless liquid with characteristic odor.

Ether with molecular formula C₂H₆O is dimethyl ether (CH₃OCH₃).

Dimethyl ether is a colorless gas.

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Wait hold up do you live in Wilson county????
7 0
3 years ago
What volume (in liters) does 3.91 moles of nitrogen gas at 5.35 atm and 323 K occupy
daser333 [38]
Moles   =  n  = 3.91 mol

                  Pressure  =  P  =  5.35 atm

                  Temperature  =  T  =  323 K

                  Volume  =  V  =  ?

Formula used: Ideal Gas Equation is used,

                                        P V  = n R  T
Solving for V,
                                           V  =  n R T / P
Putting Values,
                           V  =  (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm

                         V  =  19.36 L

5 0
3 years ago
A sample of gas at 1.10 atm has a volume of 326 mL. What is the new volume if the pressure is changed to 1.90 atm?
Brut [27]

Answer

For this we use ideal gas equation which is:

P1V1 = P2V2

P1 = 1.10 atm

V1 = 326 ml

P2 = 1.90

V2 = ?

By rearranging the ideal gas equation:

V2 =  P1V1 ÷ P2

V2 = 1.10 × 326 ÷1.90

V2 = 358.6 ÷ 1.90

V2 = 188.7 ml

8 0
3 years ago
What part of the atom is represented by the letter Z?
pashok25 [27]

Answer:

The proton of the atom

4 0
2 years ago
You have a radioactive isotope with a mass of 400 grams. The sample has a half life of 5 days. How much is left after 25 days ha
Alexeev081 [22]

Answer:

Amount left after 25 days = 12.5 g

Explanation:

Given data:

Mass of sample = 400 g

Half life of sample = 5 days

Mass left after 25 days = ?

Solution:

First of all we will calculate the number of half lives passes in given time period.

Number of half lives = Time elapsed / Half life

Number of half lives = 25 days/ 5 days

Number of half lives = 5

At time zero = 400 g

At 1st half life = 400 g/2 = 200 g

At 2nd half life = 200 g/2 = 100 g

At 3rd half life = 100 g/2 = 50 g

At 4th half life = 50 g/2 = 25 g

At 5th half life = 25 g/2 = 12.5 g

4 0
3 years ago
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