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babunello [35]
3 years ago
11

How many alcohols and ethers share the molecular formula c2h6o?

Chemistry
2 answers:
Katen [24]3 years ago
8 0

Answer:

Alcohol :CH₃-CH₂-OH (ethanol)

Ether: H₃C-O-CH₃  (dimethyl ether)

Explanation:

Alcohols are compounds containing the hydroxyl or the -OH functional group i.e. R-OH where R is an alkyl or aryl group

Ethers are compounds with a general structure, R-O-R' where R and R' are once again either alkyl or aryl groups.

The given compound has a molecular formula: C₂H₆O

Structure with 'alcohol' -OH functional group

CH₃-CH₂-OH ------- ethanol

Structure with ether functionality:

H₃C-O-CH₃     ---------dimethyl ether

Nadya [2.5K]3 years ago
4 0

Answer is: there are two compounds with molecular formula C₂H₆O, one alcohol and one ethar.

Alcohol with molecular formula C₂H₆O is ethanol or ethyl alcohol (C₂H₅OH).

Ethanol is a volatile, flammable, colorless liquid with characteristic odor.

Ether with molecular formula C₂H₆O is dimethyl ether (CH₃OCH₃).

Dimethyl ether is a colorless gas.

You might be interested in
Which of the following is the simplest ketone used as an organic solvent?
Lyrx [107]

Answer: Option (d) is the correct answer.

Explanation:

A ketone is an organic functional group that contains a carbon and oxygen atom bonded together through a double bond, that is, C=O.

For example, acetone CH_{3}-CO-CH_{3} is a ketone.

Whereas a hydrocodone is a drug which is used to relieve from moderate to sever pain.It is mostly combined with other drugs and resulting in a chemical formula C_{18}H_{21}NO_{3}.C_{4}H_{6}O_{6}.

A camphor is a volatile white color substance with chemical formula C_{10}H_{16}O. It has aromatic smell and its taste is bitter.

A menthone is also an organic compound with chemical formula C_{10}H_{18}O.

Thus, we can conclude that out of the given options the simplest ketone used as an organic solvent is acetone.

3 0
3 years ago
By what factor will the kinetic energy change if the speed of the baseball is decreased to 54.8 mi/h? Express your answer as an
Serggg [28]

Answer:

The Kinetic Energy is approximately 3 times decreased

Explanation:

A baseball weighs 5.13 oz.  

a)What is the kinetic energy, in joules, of this baseball when it is thrown by a major league pitcher at 95.o mi/h?  

b) By what factor will the kinetic energy change if the speed of the baseball is decreased to 54.8 mi/h? Express your answer as an integer.

Kinetic Energy (KE)=0.5×mass×velocity ^ 2

Kinetic Energy (KE)=0.5×mass × velocity ^ 2

Joules = kg×m^2/s^2

1 mile = 1609.344 meters

1 hour = 3600 sec

1 Oz = 28.34952 g = 0.02834952 kg

a) KE=0.5×m×v^2

=0.5×(5.13 oz × 0.02834952 kg/1 ounce)×(95 miles/h × 1609.344 m/1 mile × 1 hr/3600 s)^2

=130.761 kg×m^2/s^2 = 130.761 Joules

b) KE=0.5×m×v^2

=0.5×(5.13 oz × 0.02834952 kg/1 ounce)×(54.8 miles/h × 1609.344 m/1 mile × 1 hr/3600 s)^2

=43.51028 kg×m^2/s^2 = 43.51028 Joules

= 130.761 / 43.51028 = 3.00528,  

As such the Kinetic Energy is approximately 3 times decreased

4 0
4 years ago
(a) Compute the radius r of an impurity atom that will just fit into an FCC octahedral site in terms of the atomic radius R of t
11Alexandr11 [23.1K]

Answer:

a

The radius of an impurity atom occupying FCC octahedral site is 0.414{\rm{R}}

b

The radius of an impurity atom occupying FCC tetrahedral site is 0.225{\rm{R}} .

Explanation:

In order to get a better understanding of the solution we need to understand that the concept used to solve this question is based on the voids present in a unit cell. Looking at the fundamentals

An impurity atom in a unit cell occupies the void spaces. In FCC type of structure, there are two types of voids present. First, an octahedral void is a hole created when six spheres touch each other usually placed at the body center. On the other hand, a tetrahedral void is generated when four spheres touch each other and is placed along the body diagonal.

Step 1 of 2

(1)

The position of an atom that fits in the octahedral site with radius \left( r \right)is as shown in the first uploaded image.

In the above diagram, R is the radius of atom and a is the edge length of the unit cell.

The radius of the impurity is as follows:

2r=a-2R------(A)

The relation between radius of atom and edge length is calculated using Pythagoras Theorem is shown as follows:

Consider \Delta {\rm{XYZ}} as follows:

(XY)^ 2 =(YZ) ^2 +(XZ)^2

Substitute XY as{\rm{R}} + 2{\rm{R + R}} and {\rm{YZ}} as a and {\rm{ZX}} as a in above equation as follows:

(R+2R+R) ^2 =a ^2 +a^ 2\\16R ^2 =2a^ 2\\ a =2\sqrt{2R}

Substitute value of aa in equation (A) as follows:

r= \frac{2\sqrt{2}R -2R }{2} \\ =\sqrt{2} -1R\\ = 0.414R

The radius of an impurity atom occupying FCC octahedral site is 0.414{\rm{R}}

Note

An impure atom occupies the octahedral site, the relation between the radius of atom, edge length of unit cell and impure atom is calculated. The relation between the edge length and radius of atom is calculated using Pythagoras Theorem. This further enables in finding the radius of an impure atom.  

Step 2 of 2

(2)

The impure atom in FCC tetrahedral site is present at the body diagonal.

The position of an atom that fits in the octahedral site with radius rr is shown on the second uploaded image :

In the above diagram, R is the radius of atom and a is the edge length of the unit cell.

The body diagonal is represented by AD.

The relation between the radius of impurity, radius of atom and body diagonal is shown as follows:

AD=2R+2r----(B)

   In    \Delta {\rm{ABC}},

(AB) ^2 =(AC) ^2 +(BC) ^2

For calculation of AD, AB is determined using Pythagoras theorem.

Substitute {\rm{AC}} as a and {\rm{BC}} as a in above equation as follows:

(AB) ^2 =a ^2 +a ^2

AB= \sqrt{2a} ----(1)

Also,

AB=2R

Substitute value of 2{\rm{R}} for {\rm{AB}} in equation (1) as follows:

2R= \sqrt{2} aa = \sqrt{2} R

Therefore, the length of body diagonal is calculated using Pythagoras Theorem in \Delta {\rm{ABD}} as follows:

(AD) ^2 =(AB) ^2 +(BD)^2

Substitute {\rm{AB}} as \sqrt 2a   and {\rm{BD}} as a in above equation as follows:

(AD) ^2 =( \sqrt 2a) ^2 +(a) ^2 AD= \sqrt3a

For calculation of radius of an impure atom in FCC tetrahedral site,

Substitute value of AD in equation (B) as follows:

\sqrt 3a=2R+2r

Substitute a as \sqrt 2{\rm{R}} in above equation as follows:

( \sqrt3 )( \sqrt2 )R=2R+2r\\\\

r = \frac{2.4494R-2R}{2}\\

=0.2247R

\approx 0.225R

The radius of an impurity atom occupying FCC tetrahedral site is 0.225{\rm{R}} .

Note

An impure atom occupies the tetrahedral site, the relation between the radius of atom, edge length of unit cell and impure atom is calculated. The length of body diagonal is calculated using Pythagoras Theorem. The body diagonal is equal to the sum of the radii of two atoms. This helps in determining the relation between the radius of impure atom and radius of atom present in the unit cell.

7 0
3 years ago
How many moles of ca(oh)2 are in 25ml of 1.5 M solution?
Klio2033 [76]
Molar concentration is

C=\frac{\eta}{V}

[V]=Liters

[\eta]=mol

\eta=C*V

V=25~mL=0.025~L

\eta=1.5*0.025

\boxed{\boxed{\eta=0.0375~moles}}
6 0
4 years ago
What concentration of clo3– results when 925 ml of 0.393 m agclo3 is mixed with 685 ml of 0.283 m mn(clo3)2?
docker41 [41]

Answer;

= 0.7698 M

Explanation and solution;

AgClO3 ionizes as follows:  

AgClO3 ---> Ag^+ + ClO3^-  

Moles AgClO3 dissolved ---> (0.393 mol/L) (0.925 L) = 0.424865 mol

From the chemical equation, one mole of AgClO3 dissolving yields one mole of ClO3^- in solution.

Moles ClO3^- = 0.424 865 mol

Similarly;

Mn(ClO3)2 dissolves as follows:

Mn(ClO3)2 ---> Mn^2+ + 2ClO3^-

Moles Mn(ClO3)2 dissolved ---> (0.283 mol/L) (0.685 L) = 0.413139 mol

From the chemical equation, one mole of Mn(ClO3)2 dissolving yields two moles of ClO3^- in solution.

Moles ClO3^- = 0.413139 mol x 2 = 0.826277 mol  

Total moles ClO3^- in solution;

0.826277 mol + 0.413139 mol = 1.239416 mol  

Total volume of solution ---> 0.925 L + 0.685 L = 1.61 L  

Molarity of ClO3^- ---> 1.239416 mol / 1.61 L = 0.7698 M

6 0
3 years ago
Read 2 more answers
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