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faust18 [17]
3 years ago
6

Calculate the volume of 1M NaOH required to neutralize 200 cc of 2M HCI. What mass of sodium

Chemistry
1 answer:
Nezavi [6.7K]3 years ago
5 0

NaOH+HCl-> NaCl+H2O

1 mole of NaOH

1 mole of HCl.

To calculate volume of NaOH

CaVa/CbVb= Na/Nb

Where Ca=2M

Cb=1M

Va=200cm³

Vb=xcm³

Substitute into the equation.

2×200/1×Vb=1/1

400/Vb=1/1

Cross multiply

Vb×1=400×1

Vb=400cm³

To calculate the mass of sodium chloride, NaCl from the neutralization rxn.

Mole of NaCl=1

Molar mass of NaCl= 23+35.5=58.5

Mass=xgrammes.

Mass of NaCl=Number of moles × Molar mass.

Substitute

Mass of NaCl= 1×58.5

=58.5g

This is what I could come up with.

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inysia [295]

Answer:D.Blood

Explanation:

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How many oxygen atoms are present in a formula unit of calcium acetate?
julsineya [31]

So we end up with a total of four oxygen atoms for this calcium acetate unit and guys that truly it for this one.

6 0
3 years ago
C
Schach [20]

Answer:

2.74 M

Explanation:

Given data:

Mass of sodium chloride = 80.0 g

Volume of water = 500.0 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will convert the mL into L.

500.0 mL× 1 L /1000 mL =  0.5 L

In next step we will calculate the number of moles of sodium chloride.

Number of moles = mass/molar mass

Number of moles = 80.0 g/ 58.4 g/mol

Number of moles = 1.37 mol

Molarity:

M =  1.37 mol/ 0.5 L

M =  2.74 M

8 0
3 years ago
Sulfur dioxide gas (SO2) reacts with excess oxygen gas (O2) and excess liquid water (H2O) to form liquid sulfuric acid (H2SO4).
inessss [21]
A.2SO₂ + O₂ + 2H₂O → 2H₂SO₄
B.Moles of SO₂ = 67.2 / 22.4Moles of SO₂ = 3 molesMoles of H₂SO₄ = 3 molesMass of H₂SO₄ = 3 x 98Mass of H₂SO₄ = 294 grams
Assuming sulfuric acid to have the same density as water,density = 1000 g / LVolume = mass / densityVolume = 294 / 1000Volume = 0.29 liters of sulfuric acid

6 0
3 years ago
Read 2 more answers
It takes 2,267 joules of heat to raise the temperature of a 44.5 gram sample of a metal from 33.9°C to 288.3°C. What is the heat
ehidna [41]

Answer:

\boxed{\text{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}}}

Explanation:

The formula for the amount heat q absorbed by a substance is

q = mcΔT

where

 m = the mass of the substance

  C = the specific heat capacity of the material

ΔT = the temperature change

Data:

 q = 2267 J

m = 44.5 g

T₁ = 33.9 °C

T₂ = 288.3 °C

Calculations:

ΔT = (288.3 - 33.9) °C = 254.4 °C

\begin{array}{rcl}2267 & = & 44.5 \times C \times 254.4\\2267 & = & 11 180C\\C& = & \dfrac{2267}{11180}\\\\& = & \textbf{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}\\\end{array}

\text{The specific heat capacity of the metal is \boxed{\textbf{0.200 J$^{\circ}$C$^{-1}$g$^{-1}$}}}

5 0
3 years ago
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