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2 years ago

Which molecule is polar, based on structure?

Chemistry

1 answer:

Igoryamba2 years ago

4 0

Answer:

Sulfur dioxide (SO2)

⇒ Why is this the best option?

To determine the polarity of the molecule, there are two requirements. The first one has a variety of terminal atoms, whereas the second has a lone pair on the center atoms. The molecule is polar if one of the requirements is met; else, it is nonpolar. The oxygen atom is a terminal atom because it surrounds the sulfur atom, which is the center element in the SO2 molecule's Lewis structure. In this molecule, there are two terminal oxygen atoms. If we look at the first criterion, we can see that it is not met because it calls for the presence of two separate terminal atoms.

#SPJ2

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g Using the complex based titration system: 50.00 mL 0.00250 M Ca2 titrated with 0.0050 M EDTA, buffered at pH 11.0 determine (i

kobusy [5.1K]

Answer:

Explanation:

a).

conc of Ca²⁺ =0.0025 M

pCa = -log(0.0025) = 2.6

logK,= 10.65 So lc = 4.47 x 10.

Formation constant of Ca(EDTA)]-z= 4.47 x 10¹⁰ At pH = 11, the fraction of EDTA that exists Y⁻⁴ is $\alpha_{Y^{-4}}$ =0.81

So the Conditional Formation constant= $K_f$ =0.81x 4.47 x10¹⁰

=3.62x10¹⁰

At Equivalence point:

Ca²⁺ forms 1:1 complex with EDTA At equivalence point,

Number of moles of Ca²⁺= Number of moles of EDTA Number of moles of Ca²⁺ = M×V = 0.00250 M × 50.00 mL = 0.125 mol

Number of moles of EDTA= 0.125 mol

Volume of EDTA required = moles/Molarity = 0.125 mol / 0.0050 M = 25.00 mL

V e= 25.00 mL

At equivalence point, all Ca²⁺ is converted to [CaY²⁻] complex. So the concentration of Ca²⁺ is determined by the dissociation of [CaY²⁻] complex.

$[CaY^{2-}] = \frac{Initial,moles,of, Ca^{2+}}{Total,Volume} = \frac{0.125mol}{(50.00+25.00)mL} = 0.001667M$

${K^'}_f$

Ca²⁺ + Y⁴ ⇄ CaY²⁻

Initial 0 0 0.001667

change +x +x -x

equilibrium x x 0.001667 - x

${K^'}_f = \frac{[CaY^{2-}]}{[Ca^{2+}][Y^4]}=\frac{0.001667-x}{x.x} =\frac{0.001667-x}{x^2}\\\\x^2 = \frac{0.001667-x}{{K^'}_f}\\ \\$

$x^2=\frac{0.001667}{3.62\times10^{10}}=4.61\exp-14$

x = 2.15×10⁻⁷

[Ca+2] = 2.15x10⁻⁷ M

pca = —log(2 15x101= 6.7

3 0

4 years ago

Consider the following reactions. (Note: (s) = solid, () = liquid, and (g) = gas.)

White raven [17]

Answer:

Both are endothermic reactions.

Explanation:

Chemical equation:

1/2H₂(g) + 1/2I₂(g) → HI(g) + 6.2 kcal/mol

Chemical equation:

21.0 kcal/mol + C(s) + 2S(s) → CS₂

Both reaction are endothermic because heat is added in both of reactions.

Endothermic reactions:

The type of reactions in which energy is absorbed are called endothermic reactions.

In this type of reaction energy needed to break the bond are higher than the energy released during bond formation.

For example:

C + H₂O → CO + H₂

ΔH = +131 kj/mol

it can be written as,

C + H₂O + 131 kj/mol → CO + H₂

Exothermic reaction:

The type of reactions in which energy is released are called exothermic reactions.

In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.

For example:

Chemical equation:

C + O₂ → CO₂

ΔH = -393 Kj/mol

it can be written as,

C + O₂ → CO₂ + 393 Kj/mol

6 0

4 years ago

Determine the energy released per kilogram of fuel used. given mev per reaction, calculate energy in joules per kilogram of reac

tatuchka [14]

The energy released in nuclear reactions are far larger than that released in chemical reactions due to the release of nuclear energy from the nucleus.

<h3>Why is the energy released in a reaction?</h3>

Energy is released in a reaction due to the breaking of bonds are well as formation of bonds.

The quantity of energy released in reactions differs according to the reaction type involved.

When compared to chemical reactions, the energy released in nuclear reactions are very much higher because of the changes that occurs in the nucleus of the atoms involving nuclear energy.

The energy, E released in nuclear reactions is given by the formula below:

$E = mc^{2}$