Which molecule is polar, based on structure?

Chemistry

1 answer:

Igoryamba2 years ago

4 0

Answer:

Sulfur dioxide (SO2)

⇒ Why is this the best option?

To determine the polarity of the molecule, there are two requirements. The first one has a variety of terminal atoms, whereas the second has a lone pair on the center atoms. The molecule is polar if one of the requirements is met; else, it is nonpolar. The oxygen atom is a terminal atom because it surrounds the sulfur atom, which is the center element in the SO2 molecule's Lewis structure. In this molecule, there are two terminal oxygen atoms. If we look at the first criterion, we can see that it is not met because it calls for the presence of two separate terminal atoms.

#SPJ2

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Chloroform is an excellent solvent for extracting caffeine from water. The distribution coefficient, KD, (Cchloroform/Cwater) fo

Art [367]

The relative volumes of chloroform and water that should be used is 9:10

Concentration of solution in chloroform = $90$ ( moles of chloroform )

Concentration of solution in water = $10$ ( moles of water )

Dissociation constant at $25^oC$ ; $K_D = 10$

$K_D =$ Concentration of solution in chloroform / Concentration of solution in water

Meaning;

$K_D = \frac{\frac{mole\ of\ chloroform}{volume\ of\ chloroform} }{\frac{mole\ of\ water}{volume\ of\ water} }$

Since $90$ mole is present in chloroform and $10$ mole is present in water, Total mole of Caffeine present is $100$

Now, we substitute our given values into the equation

$10 = \frac{\frac{90}{volume\ of\ chloroform} }{\frac{10}{volume\ of\ water} }\\\\10 *\frac{10}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform} \\\\\frac{100}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}\\\\\frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{90}{100}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{9}{10}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = 9:10$