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Mariana [72]
2 years ago
13

Which molecule is polar, based on structure?

Chemistry
1 answer:
Igoryamba2 years ago
4 0

Answer:

Sulfur dioxide (SO2)

⇒ Why is this the best option?

To determine the polarity of the molecule, there are two requirements. The first one has a variety of terminal atoms, whereas the second has a lone pair on the center atoms. The molecule is polar if one of the requirements is met; else, it is nonpolar. The oxygen atom is a terminal atom because it surrounds the sulfur atom, which is the center element in the SO2 molecule's Lewis structure. In this molecule, there are two terminal oxygen atoms. If we look at the first criterion, we can see that it is not met because it calls for the presence of two separate terminal atoms.

#SPJ2

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How many molecules are in 165 g of carbon dioxide?
devlian [24]

The molar mass of CO2 is 44 grams per mole.

165 grams / 44 grams per mole of CO2 = 3.75 moles CO2

Using Avogadro’s law where 1 mole of substance equals 6.023 x 10^23 molecules

3.75 moles CO2 (6.023 x 10^23 molecules /mole) = 2.26 x 10^24 molecules CO2

3 0
3 years ago
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A line graph shows the relationship between three variables true or false
Nookie1986 [14]
The answer would be B) False cause a line graph only shows ''two'' variables, not three.
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Suggest the identity of the gas in the bubbles ​
Vlad1618 [11]

Answer:

<h3>it is hydrogen gas </h3>

3. the chemical equation is :

MgSO4 ( s ) + H2SO4 (aq)-->

MgSO4 (aq) + CO2 (g) + H2O (I)

THE IONISING OF H2SO4 IN SOLUTION IS CONPLEX

4. MAGNESIUM REACTION WITH DILUTE SULPHURIC ACID TO FORM

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hope it helps u

7 0
3 years ago
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A radioactive isotope of potassium (k) has a half-life of 20 minutes. if a 43 gram sample of this isotope is allowed to decay fo
Ksenya-84 [330]

Hello!

The half-life is the time of half-disintegration, it is the time in which half of the atoms of an isotope disintegrate.

We have the following data:

mo (initial mass) = 43 g

m (final mass after time T) = ? (in g)

x (number of periods elapsed) = ?

P (Half-life) = 20 minutes

T (Elapsed time for sample reduction) = 80 minutes

Let's find the number of periods elapsed (x), let us see:

T = x*P

80 = x*20

80 = 20\:x

20\:x = 80

x = \dfrac{80}{20}

\boxed{x = 4}

Now, let's find the final mass (m) of this isotope after the elapsed time, let's see:

m =  \dfrac{m_o}{2^x}

m =  \dfrac{43}{2^{4}}

m = \dfrac{43}{16}

\boxed{\boxed{m = 2.6875\:g}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

8 0
4 years ago
The decay of radioisotopes is a typical first order reaction. The half-life of carbon-14 (14C) is a radioactive isotope that dec
Nady [450]

Answer:

By emitting an electron and an electron antineutrino, one of the neutrons in the carbon-14 atom decays to a proton and the carbon-14 (half-life of 5,700 ± 40 years) decays into the stable (non-radioactive) isotope nitrogen-14.

Half-life: 5,730 ± 40 years

Names: carbon-14, C-14, radiocarbon

Isotope mass: 14.003241 u

8 0
3 years ago
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