Determine the length (to 1 decimal place) of the arc that subtends an angle of 2.8 radians at the centre of a circle with radius
1 answer:
Answer:
33.6 cm
Step-by-step explanation:
We can use the formula for arc length to solve this.
Where
s is the arc length
r is the radius
is the angle subtended by the arc (in radians)
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<u>The problem gives us theta = 2.8 radians and radius of the circle as 12 cm. We plug these into the formula and figure out the arc length (to 1 decimal place):</u>
2nd answer choice is right.
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Similar polygons only differ by a scaling factor. In other words, two polygons are similar if one is the scaled version of the other.
In particular, this implies that the angles are preserved, and the correspondent sides are in proportion.
These two polygons are both rectangles, so the angles are preserved. We must check the sides, and we have to check if the smaller sides are in the same proportion as the bigger sides.
So, the two rectangles are similar if the following is true.
In any proportion, the product of the inner terms must be the same as the product of the outer terms:
This is clearly false, and thus the two rectangles are not similar.
Answer:
b =
Step-by-step explanation:
Given
k = ← multiply both sides by (v - b)
k(v - b) = brt ← distribute left side
kv - kb = brt ( subtract brt from both sides )
kv - kb - brt = 0 ( subtract kv from both sides )
- kb - brt = - kv ( multiply through by - 1 to clear the negatives )
kb + brt = kv ← factor out b from each term on the left
b(k + rt ) = kv ← divide both sides by (k + rt )
b =