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BigorU [14]
3 years ago
5

Determine the length (to 1 decimal place) of the arc that subtends an angle of 2.8 radians at the centre of a circle with radius

12 cm.
13.3 cm

33.6 cm

148.0 cm

16.8 cm
Mathematics
1 answer:
victus00 [196]3 years ago
4 0

Answer:

33.6 cm

Step-by-step explanation:

We can use the formula for arc length to solve this.

s=r\theta

Where

s is the arc length

r is the radius

\theta is the angle subtended by the arc (in radians)

<u />

<u>The problem gives us theta = 2.8 radians and radius of the circle as 12 cm. We plug these into the formula and figure out the arc length (to 1 decimal place):</u>

s=r\theta\\s=(12)(2.8)\\s=33.6

2nd answer choice is right.

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Step-by-step explanation:

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Read 2 more answers
Calculators cannot display repeating decimals. Calculators always round.
andriy [413]

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1. 0.333 No

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Step-by-step explanation:

7 0
3 years ago
Find the missing side. Round to the nearest tenth.
Firdavs [7]

Answer: <em>23.7</em>

Step-by-step explanation:

<em>Let's calculate the acute angle at the base of the triangle:</em>

<em>180° - 90° - 40° = 50°</em>

<em>Find side x:</em>

\dfrac{sin \: 90^{o} }{31} =\dfrac{sin \: 50^{o} }{x}\\\\sin \: 90^{o} \cdot x=sin \: 50^{o} \cdot 31\\\\sin \: 90^{o} =1\\sin \: 50^{o} \approx 0.766\\1 \cdot x =0.766 \cdot 31\\x=23.746\\23.746 \approx 23.7

5 0
3 years ago
What does the quadratic function f(x)=x^2-10x+9 look like when it is rewritten in the form f(x) = a (x-h) + k
Tatiana [17]

ANSWER

When f(x)=x^2-10x+9 is written in the form f(x)=a(x-h)^2+k, it looks like f(x)=(x-5)^2-16


EXPLANATION

To write  f(x)=x^2-10x+9 in the form f(x)=a(x-h)^2+k, we have to complete the squares.


We add and subtract half the coefficient of x square.


f(x)=x^2-10x+(-5)^2-(-5)^2+9


The first three terms of the function is now a perfect square.

f(x)=(x-5)^2-25+9

We now simplify rto obtain,

\Rightarrow f(x)=(x-5)^2-16





6 0
3 years ago
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