Determine the length (to 1 decimal place) of the arc that subtends an angle of 2.8 radians at the centre of a circle with radius
1 answer:
Answer:
33.6 cm
Step-by-step explanation:
We can use the formula for arc length to solve this.
Where
s is the arc length
r is the radius
is the angle subtended by the arc (in radians)
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<u>The problem gives us theta = 2.8 radians and radius of the circle as 12 cm. We plug these into the formula and figure out the arc length (to 1 decimal place):</u>
2nd answer choice is right.
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When given an angle, the side opposite the angle, and another side, you have to determine how many triangles are possible or if it is not possible.
Begin with when a triangle cannot exist:
1.) measure of non-inclusive angle is less than 90° and side opposite the angle < (other side)×sin(angle measure)
2.) measure of non-inclusive angle is ≥ 90° and side opposite the angle < other side
Next determine if two triangles exist:
Only if the measure of angle is less than 90° and
(other side)×sin(non-inclusive angle measure) < opposite side < other side
Otherwise 1 triangle exist...
HERE IS WHAT YOUR PROBLEM HAS:
Non-inclusive angle measure = 22° which is < 90°
Opposite side = 13
Other side = 18.1
(other side)×sin(non-inclusive angle measure) =(18.1)×sin(22°) ≈ 6.78
So how many triangles?
6.78 < 13 < 18.1 so 2 triangles exist
Now let's find them... find angle B with law of sines
Put the following in your calculator:
This gives you the first angle B value and if you subtract it from 180 you get the other angle B value
To find the angle C for the first triangle 180 - (sum of angle A and first angle B)
Then use the law of sines to find side c for first triangle.
To find the angle C for the 2nd triangle 180 - (sum of angle A and 2nd angle B)
Then use the law of sines to find side c for 2nd triangle.
Sorry, I didn't do the calculations because my calculator is dead.
Begin with when a triangle cannot exist:
1.) measure of non-inclusive angle is less than 90° and side opposite the angle < (other side)×sin(angle measure)
2.) measure of non-inclusive angle is ≥ 90° and side opposite the angle < other side
Next determine if two triangles exist:
Only if the measure of angle is less than 90° and
(other side)×sin(non-inclusive angle measure) < opposite side < other side
Otherwise 1 triangle exist...
HERE IS WHAT YOUR PROBLEM HAS:
Non-inclusive angle measure = 22° which is < 90°
Opposite side = 13
Other side = 18.1
(other side)×sin(non-inclusive angle measure) =(18.1)×sin(22°) ≈ 6.78
So how many triangles?
6.78 < 13 < 18.1 so 2 triangles exist
Now let's find them... find angle B with law of sines
Put the following in your calculator:
This gives you the first angle B value and if you subtract it from 180 you get the other angle B value
To find the angle C for the first triangle 180 - (sum of angle A and first angle B)
Then use the law of sines to find side c for first triangle.
To find the angle C for the 2nd triangle 180 - (sum of angle A and 2nd angle B)
Then use the law of sines to find side c for 2nd triangle.
Sorry, I didn't do the calculations because my calculator is dead.
<h3>Therefore 45.87 m from which the object was dropped.</h3>
Step-by-step explanation:
Given , the velocity of free fall object is given by where v is the velocity (m/s) g is acceleration due to gravity (m/s²) and h is the the distance (m) fallen.
v = 30 m/s
g = 9.81 m/s²
⇔v² = 2gh [ squaring both sides]
Therefore 45.87 m from which the object was dropped.