1) Do 21 X^4 + 3y - 6 X^2 + 34 - (Blah) = 29 X^2 - 7 Since the only terms you have in the solution is X ^ 2 and the constant, you can get rid of 21 X^4 + 3y Now we have -6 X^2 + 34 - (Blah) = 29 X^2 - 7 -6 X^2 - (-35 X^2) = 29 X^2 34 - (41) = -7 Thus Blah is 21 X^4 + 3y - 35 X^2 + 41
2)First degree polynomials are polynomials where the highest power is 1. Thus you must subtract away 21x^4<span>-6x^2 to get 3y+34</span>