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DerKrebs [107]
3 years ago
12

Has endpoints J(13, 8) and K(–6, –6). Find the coordinates of the midpoint of .

Mathematics
1 answer:
vova2212 [387]3 years ago
3 0

Answer:

the midpoint of it is 8,-6

Step-by-step explanation:

rhgsr egh

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How to solve this problem?
makkiz [27]
The answer is c because, if u change 15% to a decimal (0.15) then u get 5,250 and when u add that to 35,000 you get 40,250
3 0
3 years ago
What is 30+10x=100 how to solve
Georgia [21]
X=7 
100-30=70 
70/10
x=7
hope this helps 
4 0
3 years ago
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Given the graph of f(x), find each of the following:
Y_Kistochka [10]

The value of the function at x = -1, 0, 1, 2, and 3 will be -4, 3, 2, -1, and 0, respectively.

<h3>What is a function?</h3>

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

From the graph of f(x), then the value of the function at x = -1, 0, 1, 2, and 3 will be given as,

x             f(x)                        Feedback

-1             -4               Point is in the fourth quadrant

0              3                      Point is in the y-axis

1               2               Point is in the first quadrant

2             -1               Point is in the second quadrant

3              0                      Point is in the x-axis

More about the function link is given below.

brainly.com/question/5245372

#SPJ1

5 0
1 year ago
B) Express 0.6363......as a rational number in its lowest term. ​
bulgar [2K]

Answer:

\frac{7}{11}

Step-by-step explanation:

We require 2 equations with the repeating digits (63) placed after the decimal point.

let x = 0.636363..... (1) multiply both sides by 100

100x = 63.6363... (2)

Subtract (1) from (2) thus eliminating the repeating digits

99x = 63 ( divide both sides by 99 )

x = \frac{63}{99} = \frac{7}{11} ← in simplest form

8 0
3 years ago
It is known that a cable with a​ cross-sectional area of 0.300.30 sq in. has a capacity to hold 2500 lb. If the capacity of the
vesna_86 [32]

Answer:

0.84 square in

Step-by-step explanation:

Since the capacity of the cable is proportional to its​ cross-sectional area. If a cable that is 0.3 sq in can hold 2500 lb then per square inch it can hold

2500 / 0.3 = 8333.33 lb/in

To old 7000 lb it the cross-sectional area would need to be

7000 / 8333.33 = 0.84 square in

5 0
3 years ago
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