Question

Twenty-four 4-inch wide square posts are evenly spaced with 5 feet between adjacent posts to enclose a square field, as shown. What is the outer perimeter, in feet, of the fence? Express your answer as a mixed number.

Answer 1

Answer:

492 0/10

Step-by-step explanation:

We have that the perimeter is 4 times the length of the side, now we know that this side "l" is given by:

l = 4 in * 24 + 23 * 5 ft

l = 96 in + 115 ft

Now, we pass the inches to pes, knowing that 1 foot equals 12 inches, so

96 in * 1 ft / 12 in = 8 ft

therefore replacing it remains:

l = 8 ft + 115 ft

l = 123 ft

now the perimeter:

p = 123 * 4

p = 492

to change to a mixed number:

4920/10 = 492 0/10

Answer 2

Answer:

129 1/3

Step-by-step explanation:

According to Alcumus, "There are 20 square posts which are not on a corner, so there are $20/4=5$ square posts on each side, not including the corner posts. Including the corner posts, there are 7 posts on a side, which means that there are 6 five-foot gaps between posts. Altogether the length of a side is $7\left(\frac{1}{3}\right)+6(5)=32\frac{1}{3}$ feet. The perimeter of the square is four times the side length, so the perimeter is $4\cdot 32\frac{1}{3}=\boxed{129\frac{1}{3}}$ feet."