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3 years ago

Can anyone help? grnheujghniuhwseruhuiwheriuh (Sorry about the letters just trying to get past the 20 words.)

Mathematics

2 answers:

babymother [125]3 years ago

8 0

Answer:

8!!!

Step-by-step explanation:

Law Incorporation [45]3 years ago

3 0

In this equation, it mentions 16 seagulls at 1 P.M. and at 3 P.M. there’s 40.

With this info, you subtract 40 by 16. After subtracting, you would get 24.

In the span of 1-3 P.M, there were 24 extra birds that appeared. If you need more explaining, please comment below

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d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

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$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$

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2 years ago

A student wrote a number pattern such that each number is 3 more that 4 times the previous number. What is the sixth term in the

Nesterboy [21]

Start with 1.
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2nd number = 1 * 4 + 3 = 7
3rd number = 7 * 4 + 3 = 31
4th = 31 * 4 + 3 = 127
5th = 127 * 4 + 3 = 511
Which means the 6th = 511 * 4 + 3, which is 2047.

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Answer:

Step-by-step explanation:

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