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VashaNatasha [74]
3 years ago
14

Which statement is true

Mathematics
1 answer:
Alinara [238K]3 years ago
5 0

The answer is C. half of 10 x 7


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Plz Help Me! I don’t have much time
JulijaS [17]

Equilateral triangles have three equal angles, so we right away know that x=60º. Then, we just solve (3(60)-70)º, which is 110º, for the answer.

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3 years ago
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A bag contains 5 blue balls, 4 red balls, and 3 orange balls. If a ball is picked from the bag at random, what is the probabilit
Marysya12 [62]

<u>Answer:</u>

  • There is a 41.7% chance that you got a blue ball.

<u>Step-by-step explanation:</u>

<u>Total number of blue balls/Total number of balls x 100 = Chance of getting a blue ball</u>

  • => 5/12 x 100
  • => 5/6 x 50
  • => 5/3 x 25
  • => 125/3
  • => 41.7

Hence, <u>there is a 41.7% chance that you got a blue ball.</u>

Hoped this helped.

BrainiacUser1357

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2 years ago
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11= r/6<br><br> Doing math homework in class right now, can’t figure it out. Not good with fractions
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11 = r/6
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2 years ago
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PLEASE HELP! 50 POINTS
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2. Page 3. Practice: Use your calculator to sketch a graph of each
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3 years ago
A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

7 0
3 years ago
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