Which statement is true

Evaluate the quotient of 1.05 x 103 and 1 x 103

agasfer [191]

Answer:

for the 1st one it is 108.15x

and the 2nd it is 103x

Step-by-step explanation:

8 0

3 years ago

PLEASE SOMEONE HELP WITH 4 QUESTIONS!<br><br><br><br><br> DOWN BELOW!!

Sever21 [200]

Answer:

1. 0.6

2. 14/25

3. 561%

4. 0.0032

5. 0.274

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Identify the corresponding word problem given the equation: x = 10.20 × 9 A) At a restaurant, William and nine friends divided t

Lynna [10]

I think it is B. and the amount that they each need to pay is $1.13

7 0

3 years ago

What is the balance after 15 years in a savings account that earns 2% interest compounded bimonthly when the initial deposit is

Ierofanga [76]

Answer:

$1348.07

Step-by-step explanation:

Hello!

<h3>Compound Interest Formula: $A = P(1 + \frac rn)^{nt}$ </h3>

A = Account Balance
P = Principle/Initial Amount
r = Rate of Interest (decimal)
n = Number of times compounded (per year)
t = Number of Years

<h3>Given Information</h3>

Account Balance = ?
Principle Amount = $1000
Rate of Interest = 0.02

Why is the Rate 0.02?

This is because we are gaining money, so the multiplier should be greater than 1. We already added 1, which is 100% so you simply add the 0.02 for the extra 2%.

Number of times compounded per year = 6

This is because it is being compounded bi-monthly, or once every 2 months. 12 months divided by 2 months is 6 months, so 6 times a year.

Number of years = 15

<h2>Solve </h2>

Solve by plugging in the given values into the formula.

$A = P(1 + \frac rn)^{nt}$
$A = 1000(1 + \frac {0.02}{6})^{6*15}$
$A = 1000(1 + 0.00333...)^{90}$
$A = 1000(1.00333...)^{90}$
$A = 1000(1.145743)$
$A \approx 1457.43$

This is really close to the first option, and since there is rounding involved with the repeating decimal, the first option should be correct.

The answer is $1348.07.

3 0

2 years ago

the following data represent the number of people aged 25-64 years covered by health insurance (private or government) in 2018.

astraxan [27]

Answer:

mean = find the total of people in such data by adding up all the totals of people represented by each age then divide that total by 2.

mean = with cumulative or frequency graphs if the numbers range individually like 25-30 and 30-35 etc and so on then you take the midpoint age and multiply it by the frequency number in new column add up both columns then divide by smaller total.

mean = histogram total number of data ie) from 270 people (80 x 0 = 0), (40 x 2 = 0) and so on multiplying the frequency. then add them all up in new column ie) 380 among 270 people = 1.4

mode = histogram highest box

median = histogram add up all data number divided by 2 and can draw this on graph as they sort of are in order ie) 15 to the left and 15 to the right

To find standard deviation you need the copulative formula and the notation change for sample shows the small m and s to represent standard deviation ie) m-n is a notation difference for samples of population's

n = number of scores ie) = 50

Ex = then sum of x = would be the collective total ie) = 270

m = 270/50 = 5.4

Ex^2 = 270 x 270 = 72900 (the square of the total population)

SS = Sum of squares = 72,900 - ( 270^2 / 50) are all the variables.

is the formula = 71,442

the root of SS -1

S^2 = 270 / (50 -1) = 270/49 = 5.51

S = sqrt S^2 = sqrt SS /n-1 = sq rt 50 = and you get your answer here.

Standard Deviation on data example here shown is;

S = sqrt 5.51 = sqrt 71442 / n-1 = sq rt 71442/ 50-1 = sq rt 71442/49 = 38.1837662 from a 270 population that exists with 50 age group 25 -75 to show the ease here and how to remember.

Just retrace and where 270 is change for total

Where 50 is put 64-25 = 39

and where n-1 is put 39-1 and always subtract first before dividing as the formula protects the brackets as seen in bold.

As your very last formula is S = SS/n-1

Step-by-step explanation:

5 0

2 years ago