Question

THE vertices of ABC are A(-2,2,B(6,2,and c(0,8). The perimeter of ABC is

Answer 1

Using the distance formula:

AB^2 = (-2-6)^2 = (2-2)^2
          = 64
    AB = 8 units
BC^2 = (6-0)^2 + (2-8)^2
          = 36 + 36
          = 72
    BC = 6 root 2
AC^2 = (-2-0)^2 + (2-8)^2
          = 4 + 36
          = 40
    AC = 2 root 10

Perimeter = 8 + 6 root 2 + 2 root 10
                 = 2 (4 + 3 root 2 + root 10) units