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olga nikolaevna [1]
3 years ago
12

A rectangle with a length 3 cm and width 3n^2-2 cm has an area of -3n cm^2. What value might n have?

Mathematics
1 answer:
aleksley [76]3 years ago
4 0
Area of rectangle could be determined with
a = l × w

plug in the algebraic expression into the formula
l × w = a
3 × (3n² - 2) = -3
9n² - 6 = -3
9n² = -3 + 6
9n² = 3
divide both side by 3
3n² = 1
n² = 1/3
n = \sqrt{ \dfrac{1}{3} }
n = \dfrac{ 1 }{ \sqrt{3} }
Rationalization of root form
n = \dfrac{1 }{ \sqrt{3}} \times \dfrac{\sqrt{3} }{ \sqrt{3}}
n = \dfrac{1}{3}  \sqrt{3}

The value of n is \boxed{\dfrac{1}{3} \sqrt{3}}
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ankoles [38]

Answer:

Check Explanation.

Step-by-step explanation:

- A sample space includes all the possible outcomes of a statistical event. It refers to all the possible results, values that a statistical event can take on.

- Any required probability = (number of outcomes in the sample space for that event)/(number of events in the sample space)

a) Joanne is considering selling a computer accessory at her store and the accessories come in white, beige, gray or black and as an optical mouse, mechanical mouse or trackball.

This means that an accessory can be white and an optical mouse, white and a mechanical mouse or white and a trackball.

This can be done for the 3 other colours.

So, the sample space for the accessory spans:

(white, optical mouse), (white, mechanical mouse), (white, trackball), (beige, optical mouse), (beige, mechanical mouse), (beige, trackball), (gray, optical mouse), (gray, mechanical mouse), (gray, trackball), (black, optical mouse), (black, mechanical mouse), (black, trackball)

The probability that someone gets beige and a mechanical mouse

Any required probability = (number of outcomes in the sample space for that event)/(number of events in the sample space)

Number of outcomes with an accessory that is beige and a mechanical mouse = 1

Number of events in the sample space = 12

The probability that someone gets beige and a mechanical mouse = (1/12) = 0.0833

b) Jackie has three pairs of jeans: Joe Brand, Levis and Seven. She also has 4 tops: red, blue, purple and pink.

The sample space for Jackie's outfits is;

(Joe Brand, red), (Joe Brand, blue), (Joe Brand, purple), (Joe Brand, pink), (Levis, red), (Levis, blue), (Levis, purple), (Levis, pink), (Seven, red), (Seven, blue), (Seven, purple), (Seven, pink)

The chance she wears the Joe Brand or Levis and a purple top.

Number of outcomes with an outfit of Joe Brand or Levis and a purple top = 2

number of outfits on the sample space = 12

The chance she wears the Joe Brand or Levis and a purple top = (1/6) = 0.1667

c) A surfer owns 5 wetsuits: brown, black, pants, shorts and green. He also owns 3 surf boards: blue, green and red.

Sample space includes

(brown, blue), (brown, green), (brown, red), (black, blue), (black, green), (black, red), (pants, blue), (pants, green), (pants, red), (shorts, blue), (shorts, green), (shorts, red), (green, blue), (green, green), (green, red)

The chance he has a green wetsuit and surfboard

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number of outcomes in the sample space = 15

The chance he has a green wetsuit and surfboard = (1/15) = 0.0667

Hope this Helps!!!

4 0
3 years ago
A rectangle length is 8cm more than three times it’s widith. The perimeter is 128 cm find the length.
Masteriza [31]
Let x = width
<span>length is 8 cm more than three times it’s width so length = 3x + 8
</span>
Perimeter of a rectangle = 2(L + W)
so
128 = 2(x + 3x + 8) solve for x (width)
128 = 2(4x + 8)
  64 = 4x + 8
  4x = 56
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width = 14 cm
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Answer:
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4 0
3 years ago
TRUE or FALSE: In the quarter circle, the radius is 4 cm and the diameter is 8 cm.
viktelen [127]

Answer: False.

Step-by-step explanation:

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The term "quarter circle" actually does refer to a fourth part of a circle, not to a circle of radius 4.

So the statement is false

6 0
3 years ago
For soccer season, Vicky wants to buy a new soccer ball, a pair of shorts, and a pair of soccer shoes. The ball costs ₹ 6890, th
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Answer:

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Step-by-step explanation:

5 0
3 years ago
Mateo compró un artefacto gastando los 3/7 de su dinero, quedándole 360 soles, ¿Cuál era el dinero que tenía Mateo al inicio?
Debora [2.8K]

Answer:

840 soles

Step-by-step explanation:

Sea la cantidad de dinero que Mateo tenía al principio = x

Mateo compró un artefacto gastando 3/7 de su dinero, dejándole 360 ​​soles,

Por eso,

3/7 × x = 360 soles

3x / 7 = 360 soles

Multiplicar cruzada

3x = 7 × 360 soles

x = 7 × 360 soles / 3

x = 840 soles

Por tanto, el dinero que tenía Mateo al principio es de 840 soles

5 0
3 years ago
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