Answer:
The rate of the slower car = 1.5km/h
Step-by-step explanation:
The distance between the two cars is 450km
Let the two cars be A and B
One car's rate is 12 kilometers per hour less than the other's
A = 12 + B
Speed = distance/time
Total distance = 45 - x + x
Let distance covered by A = x
Distance covered by B = 45 - x
For A
Speed = distance/time
A = x/3
But A = 12 + B
X = 3(12 + B) ...... (1)
For B
B = (45 - x)/3
45 - x = 3B
X = 45 - 3B ........ (2)
Equate equation 1 and 2
36 + 3B = 45 - 3B
Collect the like terms
6B = 9
B = 1.5 km/h
Therefore, the rate of the slower car is 1.5 km/ h
