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larisa86 [58]
3 years ago
10

Two cars leave towns 450 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hou

r less than the other's. If they meet in 3 hours, what is the rate of the slower car?

Mathematics
2 answers:
WARRIOR [948]3 years ago
4 0

Answer:

The rate of the slower car = 1.5km/h

Step-by-step explanation:

The distance between the two cars is 450km

Let the two cars be A and B

One car's rate is 12 kilometers per hour less than the other's

A = 12 + B

Speed = distance/time

Total distance = 45 - x + x

Let distance covered by A = x

Distance covered by B = 45 - x

For A

Speed = distance/time

A = x/3

But A = 12 + B

X = 3(12 + B) ...... (1)

For B

B = (45 - x)/3

45 - x = 3B

X = 45 - 3B ........ (2)

Equate equation 1 and 2

36 + 3B = 45 - 3B

Collect the like terms

6B = 9

B = 1.5 km/h

Therefore, the rate of the slower car is 1.5 km/ h

Kisachek [45]3 years ago
3 0

Answer:

The rate of the slower car is 69km/hr

Step-by-step explanation:

Please kindly check the attached files for explanation.

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