Question

Two cars leave towns 450 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hour less than the other's. If they meet in 3 hours, what is the rate of the slower car?

Answer 1

Answer:

The rate of the slower car = 1.5km/h

Step-by-step explanation:

The distance between the two cars is 450km

Let the two cars be A and B

One car's rate is 12 kilometers per hour less than the other's

A = 12 + B

Speed = distance/time

Total distance = 45 - x + x

Let distance covered by A = x

Distance covered by B = 45 - x

For A

Speed = distance/time

A = x/3

But A = 12 + B

X = 3(12 + B) ...... (1)

For B

B = (45 - x)/3

45 - x = 3B

X = 45 - 3B ........ (2)

Equate equation 1 and 2

36 + 3B = 45 - 3B

Collect the like terms

6B = 9

B = 1.5 km/h

Therefore, the rate of the slower car is 1.5 km/ h

Answer 2

Answer:

The rate of the slower car is 69km/hr

Step-by-step explanation:

Please kindly check the attached files for explanation.