Line BC has an equation of a line y = 2x + 3, and line EF has an equation of a line y = negative one over 2x + 4. These two equa
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Eight *(a number) plus 5*(another number) is -13.
translates to:
8(x) + 5(y) = -13
The sum of (the number) and (the other number) is 1.
translates to:
(x) + (y) = 1
We have a system of two equations involving two unknowns: x and y.
We can easily solve the system using Substitution or Elimination. Let's use Elimination this time.
We'll multiply the second equation by -8 so that the x's match up.
When we add the equations together, the x's will fall out of the equation, summing to zero. The 5y and -8y will sum to -3y and the right hand side will sum to -21.
Divide by -3,
Plug back into one of your original equations to find the value of x,
Subtract 7,
translates to:
8(x) + 5(y) = -13
The sum of (the number) and (the other number) is 1.
translates to:
(x) + (y) = 1
We have a system of two equations involving two unknowns: x and y.
We can easily solve the system using Substitution or Elimination. Let's use Elimination this time.
We'll multiply the second equation by -8 so that the x's match up.
When we add the equations together, the x's will fall out of the equation, summing to zero. The 5y and -8y will sum to -3y and the right hand side will sum to -21.
Divide by -3,
Plug back into one of your original equations to find the value of x,
Subtract 7,
Answer:
The function is defined when x > 0
Step-by-step explanation:
Functions with radicals are only undefined when the value in the radical is negative, because the root of a negative number is imaginary.
We know the function is undefined when the denominator is equal to zero. is equal to zero when x=0.
We also know that functions with radicals are undefined when the value in the radicals are negative, because the root of a negative number is imaginary. . will always be positive, but
is negative when x < 0.
So the function is undefined when x = 0, and when x < 0.
Therefore it is defined when x > 0