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Elina [12.6K]
3 years ago
6

How to multiply fractions with whole numbers without a calculator?

Mathematics
1 answer:
Leona [35]3 years ago
4 0

convert the whole number into an improper fraction then multiply

 example if you have 2 1/2 convert it to 5/2

( multiply whole number by denominator than add the numerator)

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Can you write to me explaining this please
Mnenie [13.5K]

Answer:

In addition, from the response shown, using a graphical calculator brings the following benefits:

1) You can write the system of linear equations as big as you want. This is: systems 3 * 3, 4 * 4, 5 * 5.

2) The response to systems of equations greater than 2 * 2 can be complicated when you graph the solution, therefore, the graphing calculator can be much more efficient in these cases.

3) You can write the linear equations in any way. Resolving by hand you should probably rewrite the system of equations to find the solution.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How many times does 3/4 go into 6
uranmaximum [27]
6       3
1       4
Reciprocal
6        4
1        3
Multiply normally
6*4=24
1*3=3
24/3=8
I hope this helps;)
3 0
3 years ago
Read 2 more answers
Please solve (show your work) <br><br> n - 5 + 3n ≠ 2n - 4
FromTheMoon [43]

Answer:

23.167168n−9

simplify

n-5+(3n/n(2.718282^2))(n)-4=23.167168n2−9n=23.167168n−9

3 0
2 years ago
How did newton know that 1%of 80 is 0.8
Marina86 [1]
So,

Newton knows that 1% of anything really just means moving the decimal point two places to the left.

Examples:
1% of 10 = 0.1

1% of 389,092,192 = 3,890,921.92

1% of 3.1415926 = 0.031415926

Knowing this, Newton figures that all he has to do is move the decimal place two places to the left.

1% of 80 = 0.8
8 0
3 years ago
If (ax^2 + 3x + 2b) - (5x^2+bx-3c)=3x^2-9, what is the value of A + B + C?
Rina8888 [55]

Answer:

We have the equation:

(ax^2 + 3x + 2b) - (5x^2+bx-3c)=  3x^2 - 9

First, move all to the left side.

(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0

Now let's group togheter terms with the same power of x.

(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.

This must be zero for all the values of x, then the things inside each parenthesis must be zero.

1)

a - 5 - 3 = 0

a = 3 + 5 = 8.

2)

3 - b = 0

b = 3.

3)

2b + 3c + 9 = 0

2*3 + 3c + 9 = 0

3c = -6 - 9 = -15

c = -15/3 = -5

Then we have:

a = 8, b = 3, c = -5

a + b + c = 8 + 3 - 5 = 6

8 0
3 years ago
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