Given that the first spinner has three equal sectors labelled 1, 2 and 3; and the second spinner has equal sectors labelled 3, 4, 5 and 6.
The number of possible outcomes that do not show a 1 on the first spinner is 2 (i.e. the first spinner shows 2 or 3).
The number of possible outcomes that the second spinner show the number 4 is 1 (i.e. the second spinner shows 4)
In probability, the word 'and' goes with multiplication.
Therefore, <span>the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner</span> is given by 2 x 1 = 2 possible outcomes.
i.e. the first spinner shows the number 2 and the second spinner shows the number 4 or the first spinner shows the number 3 and the second spinner shows the number 4.
THE ANSWER IS -10P.
Step-by-step explanation:
USING BY MULTIPLICATION RULE.
minus × plus = minus
then minus × minus = plus.
so we add the 4p+6p= -10p.
why -10p is come it means THE BIGGER NUMBER SIGN IS MINUS. So it's comes -10p.
<em>HOPE</em><em> </em><em>IT</em><em> </em><em>HELP</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
m<ADC = 42°
Step-by-step explanation:
Based on the inscribed angle theorem, the inscribed angle, m<ADC is ½ the measure of minor arc AC.
If minor arc is given as 84°, therefore:
m<ADC = ½(84)
m<ADC = 42°
Answer:
Hello!
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Your answer would be (C).
Hope this helped you!
