Let's call a child's ticket
and an adult's ticket
. From this, we can say:
,
since 116 tickets are sold in total.
Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus
.
Given these values, we can say:
,
since each adult ticket
costs 17,000 and each child's ticket
costs 12,750, and these costs sum to 1,653,250.
Now, we have two equations:


Let's solve:


- Find
on its own, which will allow us to substitute it into the first equation

- Substitute in
for 

- Apply the Distributive Property


- Subtract 1972000 from both sides of the equation and multiply both sides by -1

We have now found that 75 child's tickets were sold. Thus,
,
41 adult tickets were sold as well.
In sum, 41 adult tickets were sold along with 75 child tickets.
Answer:
1/18
Step-by-step explanation:
We are considering that we have 2 dices with 6 faces each (so, the probability to gettig any face in any dish is 1/6). To get an 11, we only have two ways to obtain it:
Dice 1= 6 and Dice 2 =5
or
Dice 1= 5 and Dice 2 =6
So, the probability of the event is given as:
P(Dice1=5 ∧ Dice2=6) ∪ P(Dice1=6 ∧ Dice2=5) = P(Dice1=5) x P(Dice2=6) + P(Dice1=6) x P(Dice2=5) = 1/6 x 1/6 + 1/6 x 1/6 = 1/36 + 1/36 = 2/36 = 1/18.
As 1/18 = 0,055, and 0,055 > 0,05, we consider the event as not significative (according to the definition of significance in the sentence).
Answer:
Neither.
Step-by-step explanation:
you are correct about the pattern, so it's not adding the same number and not multiplying by the same number. So it's neither.
Answer:
IT IS TRUE
Step-by-step explanation:
PLS MARK ME AS BRAINLIEST PLS PLS
Answer:
56
Step-by-step explanation: