2 years ago

I need help number 14 and 15.

Mathematics

1 answer:

Veronika [31]2 years ago

5 0

Go 2 openstudy hope that helped

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Help on number four plzzz

vesna_86 [32]

4=3
5=4
6=2
7=5
8=6
9=4
10= 16
16=31
18=36

4 0

3 years ago

Read 2 more answers

Solve the following system of equations. -3x + 5y = 80 x + 5y = 40 A. x = -10, y = 10 B. x = 2, y = 17.2 C. x = 8, y = 6.4 D. x

hammer [34]

-3x+5y=80 if the x = -10 and y = 10
x+5y=40 if the x= -10 and y= 10

5 0

3 years ago

Find the 27th term in the arithmetic sequence of 59,56,53,50

statuscvo [17]

solution:

$A_{n}=59-3(n-1)\\where, n=1,2,3,.....\\A1=59\\A2=56\\A3=53\\A_{n}=a+(n-1)dA27=59+(27-1)3\\=59-78\\=-19\\A27 term is -19$

5 0

2 years ago

WILL GET BRAILIEST FOR CORRECT ANSWER

Alex Ar [27]

Answer:

x = ± $\sqrt{20}$

Step-by-step explanation:

Given

x² = 20 ( take the square root of both sides )

x = ± $\sqrt{20}$

which can be simplified to

x = ± 2 $\sqrt{5}$

[ ± means plus or minus ]

5 0

2 years ago

Three missiles are fired at an enemy arsenal. The probabilities the individual missile will hit the arsenal are 0.75, 0.85, and

Fantom [35]

The probability that at least two of the missiles hit the arsenal:
P ( x ≥ 2 ) = P ( x = 2 ) + P ( x = 3 )
P ( x = 2 ) = 0.75 · 0.85 · 0.1 + 0.85 · 0.9 · 0.25 + 0.75 · 0.9 · 0.15 =
= 0.06375 + 0.10125 + 0.19125 = 0.35625
P ( x = 3 ) = 0.75 · 0.85 · 0.9 = 0.57375
P ( x ≥ 2 ) = 0.35625 + 0.57375 = 0.93
Answer:
The probability is 0.93 or 93%.

3 0

3 years ago