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denis23 [38]
2 years ago
6

I need help number 14 and 15.

Mathematics
1 answer:
Veronika [31]2 years ago
5 0
Go 2 openstudy hope that helped

 
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Brayden, Howard, and Vincent are on the football team. During a game, Brayden gains 1 less than 5 times the average number of ya
Gnoma [55]

Answer:  If two pair is parallel then it has no solution.

Step-by-step explanation:

Since we have given that

Let the number of gained yards by each player be y

For the case of Brayden:

Equation will be

y=5x-1\\\\y-5x=-1

For the case of Howard :

Equation will be

y=5x+1\\\\y-5x=1

For the case of Vincent :

y=4x+5\\\\y-4x=5

Since First two equations are parallel so it has no solution.

Reason:

y-5x=1\\\\y-5x=-1\\\\\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\\\\\frac{1}{1}=\frac{5}{5}\neq \frac{1}{-1}

Hence, if two pair is parallel then it has no solution.


8 0
3 years ago
Read 2 more answers
The sector of a circle with a 60 millimeters radius has a central angle measure of 30° . What is the exact area of the sector in
ASHA 777 [7]
R = 60
60^2 * pi = 3600 * pi
angle = 30°
3600pi / 30 = 120pi
the answer is 120 * pi
7 0
3 years ago
Use the multiplication property of exponents to determine if each statement is true or false.
lisabon 2012 [21]
1)
LHS:
{a}^{4}  \times  {a}^{3}  \times a \\  =  {a}^{4 + 3 + 1}  \\  =  {a}^{7}
LHS = RHS. So, the statement is true

2)
LHS:
{5}^{2}  \times  {3}^{4}  \\  = 25 \times 81 \\  =  {5}^{2}  \times  {9}^{2}  \\  =   {45}^{2}
LHS not equal to RHS. So, the statement is false

3)
LHS:
{x}^{6}  \times  {x}^{0}  \times  {x}^{2}  \times  {x}^{3}  \\  =  {x}^{6 + 0 + 2 + 3}  \\  =  {x}^{11}
LHS = RHS. So, the statement is true.

4)
LHS:
7 {m}^{2}  \times 2m \times 4 {m}^{5}  \\  = (7 \times 2 \times 4) {m}^{2 + 1 + 5}  \\  = 56 {m}^{8}
LHS = RHS. So, the statement is true.
7 0
3 years ago
Can a ray have two in point
Burka [1]
No i ray cannot have two end points. A ray only has one line that keeps on going and the other side has a endpoint where it does not keep on going like a line.
Hope this helps. (:
5 0
3 years ago
Read 2 more answers
Points E, F, and D are located on circle C. Circle C is shown. Line segments E C and D F are radii. Lines are drawn from points
elena55 [62]

Answer:

Option (1). 34°

Step-by-step explanation:

From the figure attached, CE and CD are the radii of the circle C.

Central angle CED formed by the intercepted arc DE = 68°

Since measure of an arc = central angle formed by the intercepted arc

Therefore, m∠CED = 68°

Since m∠EFD = \frac{1}{2}(m\angle ECD) [Central angle of an intercepted arc measure  the double of the inscribed angle by the same arc]

Therefore, m∠EFD = \frac{1}{2}(68)

                               = 34°

Therefore, Option (1) 34° will be the answer.

7 0
3 years ago
Read 2 more answers
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