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ASHA 777 [7]
3 years ago
6

True or False: On the Mertler’s vacation to Florida, they drove 180 miles in 3 hours before stopping for lunch. After lunch they

drove 120 miles in 2 hours before stopping for gas. Are these rates equivalent? Explain your reasoning.
Mathematics
1 answer:
natita [175]3 years ago
7 0

Answer:

true

Step-by-step explanation:

because the ratios are both 60 miles in 1 hour

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60/1 in a equivalent ratio
Elena-2011 [213]
60 /1 = 120 /2 = 180 /3

hope it helps
8 0
3 years ago
Read 2 more answers
Triangle LMN has L at (1, -1) and M at (2, 3). Triangle L'M'N' has L' at (-1, -1), M' at (3, -2), and N' is at (-3, 0). What are
fgiga [73]

Answer:

The answer is N(0,-3)

3 0
3 years ago
EF is the median of trapezoid ABCD.
BARSIC [14]

Answer:

Part A) x = 11

B) length of BC =  x + 12 =  x + 12 = 11 + 12 =23

length of EF =  4x - 18 =  4(11) - 18 = 44 - 18 =26

length of AD =  3x - 18 =  3(11) - 4 = 33 - 4 =29

Step-by-step explanation:

Median of trapezium is m=\frac{base1+base2}{2}

In provided figure, base1 is x+12 and base2 is 3x-4

A) solve for value of x

calculate the median m=\frac{base1+base2}{2}

4x-18=\frac{x+12+3x-4}{2}

4x-18=\frac{4x+8}{2}

4x-18=2x+4

2x-18=4

2x = 18 + 4

2x = 22

x = 11

B) To find the length of BC, AD and EF , put the value of x in equation of lines

length of BC =  x + 12 =  x + 12 = 11 + 12 =23

length of EF =  4x - 18 =  4(11) - 18 = 44 - 18 =26

length of AD =  3x - 4 =  3(11) - 4 = 33 - 4 =29

5 0
4 years ago
What is the equation of the line?
Neporo4naja [7]
Y=4 because y is 4 all the time
3 0
3 years ago
If anyone knows about definite integrals for calculus then please I request help! I
kicyunya [14]

Answer:

\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Integration

  • Integrals

Integration Rule [Fundamental Theorem of Calculus 1]:                                     \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Multiplied Constant]:                                                         \displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

U-Substitution

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution.</em>

  1. Set <em>u</em>:                                                                                                             \displaystyle u = 4x^{-2}
  2. [<em>u</em>] Differentiate [Basic Power Rule, Derivative Properties]:                       \displaystyle du = \frac{-8}{x^3} \ dx
  3. [Bounds] Switch:                                                                                           \displaystyle \left \{ {{x = 9 ,\ u = 4(9)^{-2} = \frac{4}{81}} \atop {x = 5 ,\ u = 4(5)^{-2} = \frac{4}{25}}} \right.

<u>Step 3: Integrate Pt. 2</u>

  1. [Integral] Rewrite [Integration Property - Multiplied Constant]:                 \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^9_5 {\frac{-8}{x^3}e^\big{4x^{-2}}} \, dx
  2. [Integral] U-Substitution:                                                                              \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}\int\limits^{\frac{4}{81}}_{\frac{4}{25}} {e^\big{u}} \, du
  3. [Integral] Exponential Integration:                                                               \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8}(e^\big{u}) \bigg| \limits^{\frac{4}{81}}_{\frac{4}{25}}
  4. Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:           \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{-1}{8} \bigg( e^\Big{\frac{4}{81}} - e^\Big{\frac{4}{25}} \bigg)
  5. Simplify:                                                                                                         \displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

4 0
3 years ago
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