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3 years ago

10

Solve and graph the absolute value inequality: |4x + 1| ≤ 5. a. number line with closed dots on −1.5 and 1 with shading going in

the opposite directions.
b. number line with open dots on −1.5 and 1 with shading in between. c. number line with closed dots on −1 and 1 with shading in between. d. number line with closed dots on −1.5 and 1 with shading in between.

1 answer:

Afina-wow [57]3 years ago

7 0

4x + 1 <= 5 ; x = 1

4x +1 >= -5 ; x = - 1.5

Now we know that x is between -1.5 and 1, so you should shade between -1.5 and 1. The circle will be closed since the equality is =< and =>

The answer is option D

Hope this helps

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A rectangle is 4 ft long and 2 ft wide. find its area in square inches.

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4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

so

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

or

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

so

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

or

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

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<em>A ratio camparing two quantities with different kinds of units is a ratio that tells the rate of change of one variable with a change in other variable.</em>

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3 years ago

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Answer:

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Substitute 3.14 for pi and 9 for radius:

A = π*r^2

A = 3.14*9^2

A = 3.14*81

A = 254.34 mm^2

Round to the nearest tenth:

254.34 ==> 254.3

Therefore, our final answer is 254.3 mm^2

Hope this helps!

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