Answer: -1 would be -d
0 -> d
1 -> f
2 -> stays same
(if this is not the right answer I'm sorry because i learned this awhile ago
this is a binomial problem: p = 0.7 and q = 0.3
a) (0.7)^6
b) (6C4)(0.7)^4(0.3)^2
c) Pr ( at least 4) = Pr(4) + Pr(5) + Pr(6) = (6C5)(0.7)^5(0.3) + (0.7)^6
d) Pr (no more than 4) = 1 - Pr(at least 4) = 1 - (answer from c)
Note the place values:
9 ones place value
. (decimal point)
3 tenths place value
4 hundredths place value
8 thousandths place value
8 ten thousandths place value
You are solving for the tenth place value. Look at the digit directly right of the tenths place value. It is the hundredths place value, which is 4.
Note that when rounding, if the number next to what you are solving for, has a value of 5 or greater, you round up. If it has a value of 4 and less, you round down. In this case, it is a 4, so round down.
9.3488 rounded to the nearest tenth is 9.3
9.3 is your answer.
13/28+17/20=−13/28+17/20=27/70
Answer:
Oohhh coooooooooooool
Step-by-step explanation:
When your finish, post a pic
I am excited!
GOOD LUCK
