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tangare [24]
3 years ago
11

Farah harvests 20 pounds of tomatoes from her garden. She needs 4 4/5 pounds to make a batch of soup. Additionally, if she uses

5.6 pounds of tomatoes to make spaghetti sauce, how many batches of soup can Farah make?
Mathematics
1 answer:
Romashka [77]3 years ago
6 0

Answer:

1 batch

Step-by-step explanation:

Farah needs 4 and 4/5 pounds of tomatoes & and additional 5 and 3/5 pounds of tomatoes to make soup.

4.8 + 5.6 = 10.5 pounds per soup

10.5*2 = 21 > 20 pounds

Farah would need one more pound of tomatoes in order to make 2 batches of soup. Therefore she can only make 1 batch.

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The sum of -7.68 and it’s additive inverse is??
Readme [11.4K]
The answer is 0. the additive inverse of a negative number is the same number but positive. to find the sum means to add them together. for example take 2 and -2. 2 is the additive inverse of -2. if you add 2+-2 the answer comes out to 0
4 0
3 years ago
Need to write steps and solve <br> thanks
nalin [4]

<u>Answer:</u>

The coordinates of endpoint V is (7,-27)

<u>Solution:</u>

Given that the midpoint of line segment UV is (5,-11) And U is (3,5).

To find the coordinates of V.

The formula for mid-point of a line segment is as follows,

Midpoint of UV is \frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}

As per the formula,  \frac{x_{1}+x_{2}}{2}=5, \frac{y_{1}+y_{2}}{2}=-11

Here x_{1}=3; y_{1}=5

Substituting the value of x_{1} we get,

\frac{3+x_{2}}{2}=5

3+x_{2}=5\times2

x_{2}=10-3

x_{2}=7

Substituting the value of x_{2} we get,

\frac{5+y_{2}}{2}=-11

5+y_{2}=-11\times2

y_{2}=-22-5

y_{2}=-27

So, the coordinates of V is (7,-27)

7 0
3 years ago
Suppose that 1 kg of Sodium-24 is reduced to 0.0156 kg in 90 hours. What is the half-life, in hours, of Sodium-24?​
N76 [4]

Answer:

14.99 hours

Step-by-step explanation:

The formula for half-life is given as,

R/R' = 2ᵃ/ᵇ...................... Equation 1

Where R= Original mass of sodium-24, R' = mass of Sodium-24 after disintegration, a = Total time taken for sodium-24 to disintegrate, b = half-life of sodiun-24.

Given: R = 1 kg, R' = 0.0156 kg, a = 90 hours

Substitute into equation 1 and solve for b

1/(0.0156) = 2⁹⁰/ᵇ

Taking the log of both side

log[1/(0.0156)] = log(2⁹⁰/ᵇ)

log[1/(0.0156)] = 90/b(log2)

90/b = log[1/(0.0156)]/log2

90/b = 6.0023

b = 90/6.0023

b =  14.99 hours

b = 14.99 hours.

Hence the half-life of Sodium-24 is 14.99 hours

7 0
3 years ago
CAN YOU HELP ME PLEASE
mamaluj [8]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
Could you please help me plzz I want to past my exam plzzzz
lorasvet [3.4K]
Pretty sure it’s D but if it is not then I don’t know
3 0
2 years ago
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