0.5x + 25 is your equation, since 25 is just a one time thing.
Answer:
![\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}](https://tex.z-dn.net/?f=%5Clog%7B%5Cdfrac%7B3%5Csqrt%7Bx%7D%28x%5E3%2B4%29%7D%7B2%7D%7D)
Step-by-step explanation:
![\log{9}+\dfrac{1}{2}\log{x}+\log{(x^3+4)}-\log{6}=\log{\left(\dfrac{9x^{\frac{1}{2}}(x^3+4)}{6}\right)}\\\\=\boxed{\log{\dfrac{3\sqrt{x}(x^3+4)}{2}}}\qquad\text{matches choice A}](https://tex.z-dn.net/?f=%5Clog%7B9%7D%2B%5Cdfrac%7B1%7D%7B2%7D%5Clog%7Bx%7D%2B%5Clog%7B%28x%5E3%2B4%29%7D-%5Clog%7B6%7D%3D%5Clog%7B%5Cleft%28%5Cdfrac%7B9x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%28x%5E3%2B4%29%7D%7B6%7D%5Cright%29%7D%5C%5C%5C%5C%3D%5Cboxed%7B%5Clog%7B%5Cdfrac%7B3%5Csqrt%7Bx%7D%28x%5E3%2B4%29%7D%7B2%7D%7D%7D%5Cqquad%5Ctext%7Bmatches%20choice%20A%7D)
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The applicable rules of logarithms are ...
log(ab) = log(a) +log(b)
log(a/b) = log(a) -log(b)
log(a^b) = b·log(a)
Answer:
And for this case ![r =0.45](https://tex.z-dn.net/?f=%20r%20%3D0.45)
The % of variation is given by the determination coefficient given by
and on this case
, so then the % of variation explained is 20.25%.
The proportion of the variability seen in final grade performance that can be predicted by math ability scores is 20.25%.
Step-by-step explanation:
For this case we asume that we fit a linear model:
![y = mx+b](https://tex.z-dn.net/?f=%20y%20%3D%20mx%2Bb)
Where y represent the final grade and x the math ability scores
Where:
And we can find the intercept using this:
The correlation coeffcient is given by:
And for this case ![r =0.45](https://tex.z-dn.net/?f=%20r%20%3D0.45)
The % of variation is given by the determination coefficient given by
and on this case
, so then the % of variation explained is 20.25%.
The proportion of the variability seen in final grade performance that can be predicted by math ability scores is 20.25%.
Answer:
21
Step-by-step explanation:
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