5y(2x-1)=y(x+2)+20, x=3
2 answers:
5y(2x-1)=y(x+2)+20, x=3
Step 1: Substitute x with 3
5y(2(3) - 1) = y(3 + 2) + 20
Step 2: Combine like terms in the parentheses
5y(6 - 1) = y(3 + 2) + 20
5y(5) = y(3 + 2) + 20
5y(5) = y(5) + 20
Step 2: Distribute the number outside the parentheses to the numbers inside the parentheses
25y = 5y + 20
Step 3: Combine like terms by subtracting 5y to both sides
25y-5y = (5y-5y) + 20
20y = 20
Step 4: Divide 20 to both sides to isolate y
y = 1
Check:
5(1) (2(3) - 1) = 1(3+2) + 20
5(6-1) = 1(5) + 20
5(5) = 5 + 20
25 = 25
Hope this helped!
You might be interested in
Answer:
See attached diagram
Step-by-step explanation:
Graph the solution of the inequality First, draw the dotted line
(dotted because the sign of the inequality is <). Then determine wich part of the coordinate plane should be shaded. Since the origin's coordinates satisfy the inequality, then this point should belong to the region (red part on the diagram).
Graph the solution of the inequality First, draw the solid line
(solid because the sign of the inequality is ≥). Then determine wich part of the coordinate plane should be shaded. Since the origin's coordinates satisfy the inequality, then this point should belong to the region (blue part on the diagram).
The intersection of both regions is the solution of the system of two inequalities.
