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Stells [14]
3 years ago
8

Never text and drive! Discuss with your parents the use of your cell phone when driving. Explain to them the one situation when

it would be appropriate to talk on your cell phone. Then write the situation you spoke with them about.
Physics
1 answer:
DanielleElmas [232]3 years ago
7 0
One reason that it would be appropriate to talk on your cell phone, could be reporting an accident. For instance, a car crash, a sign in the road anything regarding safety of drivers.
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A 23.0 kg iron weightlifting plate has a volume of 2920 cm3 . what is the density of the iron plate in g/cm3?
yanalaym [24]
The first thing you should know for this case is that density is defined as the quotient between mass and volume:
 D = M / V
 In addition, you should keep in mind the following conversion:
 1Kg = 1000g
 Substituting the values we have:
 D = (23.0 * 1000) / (2920) = 7.88 g / cm ^ 3
 answer
 the density of the iron plate is 7.88 g / cm ^ 3
8 0
3 years ago
A mother is pulling a sled at constant velocity by means of a rope at 37°. The tension on the rope is 120 N. Mass of children pl
nordsb [41]

Answer:

Please find the complete solution in the attached file.

Explanation:

3 0
3 years ago
What best describes hooke’s equation?
NeX [460]
The spring balance
F =ke
6 0
3 years ago
A charge of 31.0 μC is to be split into two parts that are then separated by 24.0 mm, what is the maximum possible magnitude of
miskamm [114]

Answer:

1.72 x 10³ N.

Explanation:

When a charge is split equally and placed at a certain distance , maximum electrostatic force is possible.

So the charges will be each equal to

31/2 = 15.5 x 10⁻⁶ C

F = K Q q / r²

= \frac{9\times10^9\times(10.5)^2\times10^{-12}}{(24\times10^{-3})^2}

= 1.72 x 10³ N.

8 0
3 years ago
A truck traveling at a velocity of 33m/s comes to a halt by decelerating at 11m/s^2. How far does the truck travel in the proces
snow_lady [41]

Answer:

<u><em>The truck was moving 16.5 m/s during the time it took to stop, which was 3 seconds. </em></u>

  • <u><em>Initial velocity = 33 m/s</em></u>
  • <u><em>Final velocity = 0 m/s</em></u>
  • <u><em>Average velocity = (33 + 0) / 2  m/s = 16.5 m/s</em></u>

Explanation:

  1. <u><em>First, how long does it take the truck to come to a complete stop?</em></u>
  1. <u><em>( 33 m/s ) / ( 11 m / s^2 ) = 3 seconds</em></u>
  1. <u><em>Then we can look at the average velocity between when the truck started decelerating and when it came to a complete stop. Because the deceleration is constant (always 11m/s^2) we can use this trick.</em></u>
4 0
3 years ago
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