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LenKa [72]
3 years ago
9

When it reaches an altitude of 3600 m, where the temperature is 5.0∘C and the pressure only 0.68 atm, how will its volume compar

e to that at sea level?
Physics
1 answer:
dalvyx [7]3 years ago
7 0

Answer:

The question was incomplete. Here is the complete question.

Explanation:

A helium-filled balloon escapes a child’s hand at sea level and 20.0C. When it reaches an altitude of 3600 m, where the temperature is 5.0∘C and the pressure only 0.68 atm, how will its volume compare to that at sea level?

The ideal gas equation:

PV = nRT

P = absolute pressure

V = Volume of a gas

n = no of moles of a gas

R = ideal gas constant

T = Absolute temperature of a gas

For initial and final states:

P_{i}V_{i} = nRT_{i}   \\P_{f}V_{f} = nRT_{f}   \\\frac{V_{f} }{V_{i} } = \frac{P_{i}T_{f} }{P_{f}T_{i} }

= 1.4

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The mass of an object with 500 J of kinetic energy moving with a velocity of 5 m/s is
Ann [662]

40kg

Explanation:

Given parameters:

Kinetic energy  = 500J

Velocity = 5m/s

Unknown:

Mass of the object = ?

Solution:

Kinetic energy is the energy due to motion of a body. It is expressed as:

          K.E = \frac{1}{2} mv²

  m is the mass of the body

  v is the velocity

 To find the mass, make it the subject of the expression:

         m = \frac{2 K.E}{v[tex]^{2}}[/tex]

          m =   \frac{2 x 500}{5[tex]^{2}}[/tex] = 40kg

Learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

4 0
3 years ago
Please solve this for me ​
uranmaximum [27]

See if you get the answer with this formulae.

6 0
3 years ago
A box of unknown mass is sliding with an initial speed vi = 5.60 m/s across a horizontal frictionless warehouse floor when it en
Maksim231197 [3]

We know that the Delta E + W(Work done by non-conservative forces) = 0 (change of energy)

In here, the non-conservative force is the friction force where f = uN (u =kinetic friction coefficient) 

W= f x d = uNd ; N=mg 
Delta E = 1/2 mV^2 -1/2mVi^2 

umgd + 1/2mV^2 - 1/2mVi^2 = 0 (cancel out the m term) 

This will then give us: 

1/2Vi^2-ugd = 1/2V^2 

V^2 = Vi^2 - 2ugd

So plugging in our values, will give us:

V= Sqrt (5.6^2 -2.3^2)

=sqrt (26.07)

= 5.11 m/s 

 

6 0
3 years ago
You want to create a new warming appliance that is safe. Which type of electromagnetic wave would be most useful to investigate?
NARA [144]
Infrared waves. The other 3 would hurt you because they are below the UV scale of 400 nanometers. Infrared is light that wouldn't harm you
4 0
3 years ago
Read 2 more answers
An 888.0 kg elevator is moving downward with a velocity of 0.800 m/s. It decelerates uniformly and comes to a stop in a distance
bagirrra123 [75]

Answer:

The value of tension on the cable T = 1065.6 N

Explanation:

Mass = 888 kg

Initial velocity ( u )= 0.8 \frac{m}{sec}

Final velocity ( V ) = 0

Distance traveled before come to rest = 0.2667 m

Now use third law of motion V^{2} = u^{2} - 2 a s

Put all the values in above formula we get,

⇒ 0 = 0.8^{2} - 2 × a ×0.2667

⇒ a = 1.2 \frac{m}{sec^{2} }

This is the deceleration of the box.

Tension in the cable is given by T = F = m × a

Put all the values in above formula we get,

T = 888 × 1.2

T = 1065.6 N

This is the value of tension on the cable.

5 0
3 years ago
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