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pav-90 [236]
2 years ago
15

A well is being dug. A 4.5-kg bucket is filled with 28.0 kg of dirt and pulled vertically upward at a constant speed through a d

istance of 9.0 m. Determine the work done on the filled bucket in raising out of the hole.
Physics
1 answer:
andreyandreev [35.5K]2 years ago
4 0

The work done on the filled bucket in raising out of the hole is 2, 925 Joules

<h3>How to determine the work done</h3>

Using the formula:

Work done = force * distance

Note that force = mass * acceleration

F = mg + ma

F = 4. 5 * 10 + 28 * 10

F = 45 + 280

F = 325 Newton

Distance = 9m

Substitute into formula

Work done = 325 * 9

Work done = 2, 925 Joules

Therefore, the work done is 2, 925 Joules

Learn more about work done here:

brainly.com/question/25573309

#SPJ1

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What types of natural phenomena could serve as time standards?
Delvig [45]

Answer: The rising and setting of the Sun.

The appearance and disappearance of the Moon.

Changes in season.

Appearance and disappearance of the Stars.

Explanation: The rising and setting of the Sun helps can be used as a standard to determine time since the rissing and setting of the Sun occurs at similar time and interval in a given geographical ocation.

The appearance and disappearance of the Moon which occurs during the night and early hours of the morning is similar in a given geographical locationation so it can be used as a standard for Time.

Change in season is another natural phenomenon which occurs at similar times in a given geographical location like Winter/summer, rainy/dry etc can be used as standards for time.

The appearance and disappearance of the Stars can also b used as standards for time in a given geographical location.

5 0
3 years ago
I SEE YOU....STOO CHEATING!!!!!!
professor190 [17]
BAHHAHAJA WHY IS THIS SO FUNNY
4 0
3 years ago
A child and sled with a combined mass of 50.0 kg slide down a frictionless slope. if the sled starts from rest and has a speed o
Furkat [3]
            <span> Using conservation of energy

Potential Energy (Before) = Kinetic Energy (After)

mgh = 0.5mv^2

divide both sides by m

gh = 0.5v^2

h = (0.5V^2)/g

h = (0.5*2.2^2)/9.81

h = 0.25m

</span>
4 0
3 years ago
Read 2 more answers
How far would a horse that rides at 8.1 m/s travel and 8.5 minutes
Xelga [282]
V = S/t

The time is in minutes, it needs to be converted to seconds, because the Velocity 8.1meters/second.

1 min -------- 60 secs
8.5 min -------- x secs
-> x = 8.5 . 60
-> x = 510secs

-> 8.1 = S/510
-> 510 x 8.1 = S
-> S = 4131 meters
3 0
4 years ago
A woman is 1.6 m tall and has a mass of 50 kg. She moves past an observer with the direction of the motion parallel to her heigh
eduard

To solve this problem it is necessary to apply the concepts related to linear momentum, velocity and relative distance.

By definition we know that the relative velocity of an object with reference to the Light, is defined by

V_0 = \frac{V}{\sqrt{1-\frac{V^2}{c^2}}}

Where,

V = Speed from relative point

c = Speed of light

On the other hand we have that the linear momentum is defined as

P = mv

Replacing the relative velocity equation here we have to

P = \frac{mV}{\sqrt{1-\frac{V^2}{c^2}}}

P^2 = \frac{m^2V^2}{1-\frac{V^2}{c^2}}

P^2 = \frac{P^2V^2}{c^2}+m^2V^2

P^2 = V^2 (\frac{P^2}{c^2}+m^2)

V^2 = \frac{P^2}{\frac{P^2}{c^2}+m^2}

V^2 = \frac{(2.1*10^10)^2}{\frac{(2.1*10^10)^2}{(3.8*10^8)^2}+50^2}

V = 2.81784*10^8m/s

Therefore the height with respect the observer is

l = l_0*\sqrt{1-\frac{V^2}{c^2}}

l = 1.6*\sqrt{1-\frac{(2.81*10^8)^2}{(3*10^8)^2}}

l = 0.56m

Therefore the height which the observerd measure for her is 0.56m

8 0
3 years ago
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