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Anni [7]
3 years ago
13

Which of the following expressions are equivalent? I. 4(6 - x) II. 4 + (6 - x) III. 6(4 - x) IV. (6 - x) + (6 - x) + (6 - x) + (

6 - x) A. I and IV B. I, III and IV C. I and III D. II, III and IV
Mathematics
1 answer:
Romashka [77]3 years ago
5 0

Answer:

A. I and IV

Step-by-step explanation:

I. 4(6 - x)

II. 4 + (6 - x)

III. 6(4 - x)

IV. (6 - x) + (6 - x) + (6 - x) + (6 - x)

Let's keep them in the simplest expressions.

I. 4(6 - x)

4(6) - 4x

24 - 4x

II. 4 + (6 - x)

4 + 6 - x

10 - x

III. 6(4 - x)

6(4) - 6x

24 - 6x

IV. (6 - x) + (6 - x) + (6 - x) + (6 - x)

6 - x + 6 - x + 6 - x + 6 - x

6 + 6 + 6 + 6 - x - x - x - x

24 - 4x

Only I and IV have the same result.

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Alona [7]
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4 0
3 years ago
(i) Write the expansion of (x + y)² and (x - y)². (ii) Find (x + y)² - (x - y)² (iii) Write 12 as the difference of two perfect
zaharov [31]

Answer:

1a (x + y)² = x² + 2xy + y²

1b. (x - y)² = x² - 2xy + y²

2. (x + y)² - (x - y)² = 4xy

3. 4² – 2² = 12

Step-by-step explanation:

1a. Expansion of (x + y)²

(x + y)² = (x + y)(x + y)

(x + y)² = x(x + y) + y(x + y)

(x + y)² = x² + xy + xy + y²

(x + y)² = x² + 2xy + y²

1b. Expansion of (x - y)²

(x - y)² = (x - y)(x - y)

(x - y)² = x(x - y) - y(x - y)

(x - y)² = x² - xy - xy + y²

(x - y)² = x² - 2xy + y²

2. Determination of (x + y)² - (x - y)²

This can be obtained as follow

(x + y)² = x² + 2xy + y²

(x - y)² = x² - 2xy + y²

(x + y)² - (x - y)² = x² + 2xy + y² - (x² - 2xy + y²)

= x² + 2xy + y² - x² + 2xy - y²

= x² - x² + 2xy + 2xy + y² - y²

= 2xy + 2xy

= 4xy

(x + y)² - (x - y)² = 4xy

3. Writing 12 as the difference of two perfect square.

To do this, we shall subtract 12 from a perfect square to obtain a number which has a perfect square root.

We'll begin by 4

4² – 12

16 – 12 = 4

Find the square root of 4

√4 = 2

4 has a square root of 2.

Thus,

4² – 12 = 4

4² – 12 = 2²

Rearrange

4² – 2² = 12

Therefore, 12 as a difference of two perfect square is 4² – 2²

7 0
3 years ago
I need answers to these questions
GalinKa [24]

Answer is in the attached file...

8 0
2 years ago
1st answer gets brainliest!!!
Nastasia [14]
The apothem of this is 13
7 0
3 years ago
The circle passes through the point (4.5,0). What is its radius?
Andreyy89

Answer:

4.5 units

Step-by-step explanation:

In this case, if we draw the point on the xy cartesian plane, we know that the value of "x" is 4.5 and the value of "y" is 0.

Which means that when I draw this in any way, the maximum value it will take is 4.5 units, therefore the radius should not exceed this value, nor should it be less than 4.5 units since the circle would be distorted.

Which means that the radius is 4.5 units

4 0
3 years ago
Read 2 more answers
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