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3 years ago

10

a stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. determine the depth of the well. .

..?

1 answer:

Sunny_sXe [5.5K]3 years ago

8 0

D = ut + 1/2 at^2

d = 0 x 3.41 + 1/2 x 9.8 x 3.14 ^2

d = 48.31

Hope this helps

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(d) Suppose you use a spring to launch a payload horizontally from the asteroid so that the payload ends up far from the asteroi

nydimaria [60]

Answer:

ks= 133.2 N/m

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3 years ago

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Physics Question (attached)

hammer [34]

Answer:

The answer is " $\bold{10.6 \ \ \frac{m}{s^2}}$ "

Explanation:

The Formula of acceleration:

$\bold{a= \frac{v-v_0}{t}}$

Given value:

$t= 50\\v= 856\\v_0= 324$

Calculating the acceleration:

$\to a = \frac{(856 - 324)}{50}\\\\$

$= \frac{(532)}{50}\\\\= \frac{(106.4)}{10}\\\\= 10.64 \ \ \frac{ m}{s^2}$

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3 years ago