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3 years ago

An object initially at rest experiences an acceleration of 12 m/s2 for a time of 5 s. How far will it travel during that time?

Physics

1 answer:

pogonyaev3 years ago

6 0

Answer:

150 meters

Explanation:

d = .5a*t^2 + v0*t

d = displacement

v0 = initial velocity, 0 because the object was initially at rest

a = acceleration, which is 12

t = time, which is 5

d = (12/2)*(5^2)+0 = 6*25 = 150

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Where,

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Where,

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$\frac{\Delta m}{\Delta t} = \rho_w Av$

Where,

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