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zlopas [31]
3 years ago
8

An object initially at rest experiences an acceleration of 12 m/s2 for a time of 5 s. How far will it travel during that time?

Physics
1 answer:
pogonyaev3 years ago
6 0

Answer:

150 meters

Explanation:

d = .5a*t^2 + v0*t

d = displacement

v0 = initial velocity, 0 because the object was initially at rest

a = acceleration, which is 12

t = time, which is 5

d = (12/2)*(5^2)+0 = 6*25 = 150

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A man goes 150 m due east and then 200 m due north how far is he from starting point
grin007 [14]

Answer:

250 m

Explanation:

Since North and East are 90 degrees from each other, we can treat this as a right-angled triangle, with the distance in each direction being the sides and the distance from the starting point being the hypotenuse.

Hence, sqrt(150^2+200^2) = 250 m.

Hope this helped!

7 0
2 years ago
Part A: Explain why x = 5 makes 4x − 1 ≤ 19 true but not 4x − 1 < 19. (5 points) Part B: What value from the set {6, 7, 8, 9,
Elis [28]

Answer:

A: ≤ means less than OR equal to. < only means less than

B: 9

Explanation:

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B: 47 - 2, 45. Then 5 x 9 equals 45. So 5 x 9 equals 45, then add 2 would equal 47.

Hope this helps <3

5 0
3 years ago
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Kay [80]

Answer:

He examined covered and uncovered meat to determine that maggots came from eggs.

In other other words A

5 0
3 years ago
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Explanation:

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8 0
2 years ago
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I say Reverse Fault, Hope this helps :)
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