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zlopas [31]
3 years ago
8

An object initially at rest experiences an acceleration of 12 m/s2 for a time of 5 s. How far will it travel during that time?

Physics
1 answer:
pogonyaev3 years ago
6 0

Answer:

150 meters

Explanation:

d = .5a*t^2 + v0*t

d = displacement

v0 = initial velocity, 0 because the object was initially at rest

a = acceleration, which is 12

t = time, which is 5

d = (12/2)*(5^2)+0 = 6*25 = 150

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MA_775_DIABLO [31]

The correct definition of a fracture is break in the bone

<u>Explanation:</u>

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4 0
3 years ago
The total mass of the train and its passengers is 750000kg. The train is traveling at a speed of 84m/s. The driver applies the b
fiasKO [112]

Answer:

|F| = 393750  N

Explanation:

Given that,

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Final speed, v = 42 m/s

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F = ma

F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{750000\times (42-84)}{80}\\\\F=-393750\ N

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4 0
3 years ago
What is a tool that measures the size of a force
MakcuM [25]
<span>this is a dynamometer</span>
3 0
3 years ago
Garret's swimming coach is giving him important and helpful tips to improve his swimming skills. Which gesture suggests that Gar
bogdanovich [222]

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7 0
3 years ago
Read 2 more answers
At the same moment from the top of a building 3.0 × 10 2 m tall, one rock is dropped and one is thrown downward with an initial
Bess [88]
The equation that relates distance, velocities, acceleration, and time is,
                   d = V₀t + 0.5gt²
where d is distance,
V₀ is the initial velocity,
t is time, and 
g is the acceleration due to gravity (equal to 9.8 m/s²)

(1) Dropped rock,
                  (3 x 10² m ) = 0(t) + 0.5(9.8 m/s²)(t²)
The value of t from this equation is 24.73 s

(2) Thrown rock with V₀ = 26 m/s
                (3 x 10² m) = (26)(t) + 0.5(9.8 m/s²)(t²)
The value of t from the equation is 5.61 s

The difference between the tim,
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          difference = 19.12 s

<em>ANSWER: 19.12 s</em>
5 0
3 years ago
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