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zlopas [31]
3 years ago
8

An object initially at rest experiences an acceleration of 12 m/s2 for a time of 5 s. How far will it travel during that time?

Physics
1 answer:
pogonyaev3 years ago
6 0

Answer:

150 meters

Explanation:

d = .5a*t^2 + v0*t

d = displacement

v0 = initial velocity, 0 because the object was initially at rest

a = acceleration, which is 12

t = time, which is 5

d = (12/2)*(5^2)+0 = 6*25 = 150

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tia_tia [17]
Hi!

The energy of the block is 4 m/s

To calculate this, you need to use the equation for kinetic energy. The block is sliding (i.e. it's moving). If the object is sliding across a level surface, the only energy it has is kinetic energy, because there is no change in potential energy (which changes with height). So, the mechanical energy will be pure kinetic energy. The equation is the following, derived from the expression for kinetic energy:

v= \sqrt{ \frac{2*Ke}{m}}=\sqrt{ \frac{2*20 (kg*m^{2}*s^{-2}) }{2,5kg}}=4 m/s

Have a nice day!
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A stone is thrown upward with an initial upward velocity of 15 m/s from a
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