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3 years ago

An object initially at rest experiences an acceleration of 12 m/s2 for a time of 5 s. How far will it travel during that time?

Physics

1 answer:

pogonyaev3 years ago

6 0

Answer:

150 meters

Explanation:

d = .5a*t^2 + v0*t

d = displacement

v0 = initial velocity, 0 because the object was initially at rest

a = acceleration, which is 12

t = time, which is 5

d = (12/2)*(5^2)+0 = 6*25 = 150

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A beam of protons is directed in a straight line along the positive zz ‑direction through a region of space in which there are c

Zinaida [17]

Answer:

The magnitude is $B = \frac{450}{7.9* 10^5}$

The direction is the positive x axis

Explanation:

From the question we are told that

The electric field is E = 450 V/m in the negative y ‑direction

The speed of the proton is $v= 7.9* 10^5\ m/s$ in the positive z direction

Generally the overall force acting on the proton is mathematical represented as

$F_E = q(\vec E + \vec v * \vec B)$

Now for the beam of protons to continue un-deflected along its straight-line trajectory then $F_E =0$

$0 = q( E (-y) + v(z) * \vec B)$

=> $E\^y = v \^ z * \vec B$

Generally from unit vector cross product vector multiplication

$\^ z \ * \ \^ x = \^ y$

So the direction of B (magnetic field must be in the positive x -axis )

$E\^y = v \^ z * B\^ x$

=> $E\^y = vB ( \^ z * \^ x)$

=> $E\^y = vB ( \^y)$

=> $E = vB$

=> $B = \frac{450}{7.9* 10^5}$

=> $B = 0.0005696 \ T$

6 0

4 years ago

Once carbon begins burning in the core of a high-mass star, the outer layers begin to fall inward, driving up the fusion rates a

sammy [17]

Answer:

Fusion rates and star evolution increase rapidly because of the conversion of hydrogen molecules to helium.

Explanation:

At the early stage of a star mass, hydrogen atoms are produced. After a few billion years, these hydrogen atoms formed at the core of the star mass begin to fuse on the external side of the core. Hydrogen atoms get rapidly fused, resulting to a contraction of the star core, and as more hydrogen atoms get fused, helium atoms are formed.

This action results into rapid into a rapid and violent burning action of hydrogen atoms around the core.

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3 years ago

13. A lever does 5.0 J of work on a 0.10-kg ball bearing in a pinball machine. The ball's

shusha [124]

Answer:

The resulting speed of the ball is;

10 m/s

Explanation:

The given parameters are;

The amount of work done by the lever = 5.0 J

The mass of the ball on which the work is done, m = 0.10 kg

By the principle of conservation of energy, we have;

The work done by the lever = The kinetic energy. K.E., gained by the ball

The kinetic energy, K.E., is given by K.E. = 1/2·m·v²

Where, for the ball, we have;

m = The mass of the ball

v = The resulting speed of the ball

Therefore, by substituting the known values, we have;

The work done by the lever = 5.0 J = The kinetic energy. K.E., gained by the ball = 1/2 × m × v² = 1/2 × 0.10 kg × v²

∴ 5.0 J = 1/2 × 0.10 kg × v²

v² = 5.0 J/(1/2 × 0.10 kg) = 100 m²/s²

v = √(100 m²/s²) = 10 m/s

The resulting speed of the ball, v = 10 m/s.

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