Answer:
The linear acceleration of the car is 2.86m/s².
Explanation:
First of all, we have that the linear acceleration of the car and the tires is the same, because it moves ahead without disassembling itself. So, we only have to calculate the linear acceleration of the tires.
Next, it is known that the linear and angular acceleration are related by the formula:
Finally, we plug in the given values in order to calculate the acceleration:
It means that the linear acceleration of the car is 2.86m/s².
The answer to this question is A.
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Answer:
34.3 m/s
Explanation:
Newton's Second Law states that the resultant of the forces acting on the car is equal to the product between the mass of the car, m, and the centripetal acceleration 
(because the car is moving of circular motion). So at the top of the hill the equation of the forces is:
where
(mg) is the weight of the car (downward), with m being the car's mass and g=9.8 m/s^2 is the acceleration due to gravity
R is the normal reaction exerted by the road on the car (upward, so with negative sign)
v is the speed of the car
r = 0.120 km = 120 m is the radius of the curve
The problem is asking for the speed that the car would have when it tires just barely lose contact with the road: this means requiring that the normal reaction is zero, R=0. Substituting into the equation and solving for v, we find:
