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3 years ago

List two pieces of evidence related to this picture

Physics

2 answers:

lesya [120]3 years ago

7 0

Crash
Someone upset about the crash

tatyana61 [14]3 years ago

4 0

Answer:

there was a crash you can tell cause of the 2 cars the dog is curious on what happened, you can tell because the dog is looking at the cash

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arlene is to walk across a high wire strung horizontally between two buildings 10.0m apart. The sag in the rope when she is at t

Ipatiy [6.2K]

We are given with a force in the middle of a rope measuring 10 m and an angle of sagging of 10 degrees from the horizontal. The tension of the rope is equal to the hypotenuse of the right triangle.

sin 10 = 50 kg * 9.8 m/s2 / T
Tension = 2821. 80 N

4 0

3 years ago

Read 2 more answers

The importance of the Miller–Urey experiment is that (a) it proved beyond doubt that life could have arisen naturally on the you

Blababa [14]

Answer:

Explanation:

5 0

3 years ago

A parallel-plate capacitor is charged and then is disconnected from the battery. By what factor does the stored energy change wh

andrew-mc [135]

Answer:

0.5

Explanation:

The energy of a charged capacitor is given by $\frac{1}{2}QC$ where $Q$ is the charge on it and $C$ is its capacitance. The capacitance is defined, geometrically, as

$\dfrac{\epsilon A}{d}$

where $\epsilon$ is a constant that is determined by the material between the plates, $A$ is the area of the plates and $d$ is the distance between them. It is then that the capacitance is linearly inversely proportional to the separation distance; as the distance increases, the capacitance reduces.

Because it is linear, when the separation distance is doubled, other factors remaining constant, the capacitance is halved. Because the capacitance is halved, the energy is halved.

Let's see the mathematics.

Initial capacitance, $C_1$ at initial separation, $d_1$

$C_1=\dfrac{\epsilon A}{d_1}$

If separation is doubled, separation becomes $d_2=2d_1$ . Then the capacitance becomes

$C_2=\dfrac{\epsilon A}{d_2}$

$C_2=\dfrac{\epsilon A}{2d_1}$

$C_2=0.5\dfrac{\epsilon A}{d_1}$

$C_2=0.5C_1$

Initial energy, $E_1=\frac{1}{2}QC_1$

Final energy, $E_2=\frac{1}{2}QC_2= \frac{1}{2}Q\times0.5C_1$

$E_2=0.5\times\frac{1}{2}QC_1=0.5E_1$

Hence, $\frac{E_2}{E_1}=0.5$

5 0

3 years ago

Older railroad tracks in the U.S. are made of 12 m-long pieces of steel. When the tracks are laid, gaps are left between the sec

Shkiper50 [21]

Answer:

0.005 m

Explanation:

length of steel (L°) = 12 m

initial temperature (T) = 16 degrees

expected temperature (T') = 50 degrees

We can find how large the gaps should be if the track is not to buckle when the temperature is as high as 50 degrees from the formula below

ΔL = ∝L°ΔT where

ΔL = expansion / gap
∝ = linear expansion coefficient of steel = $12x10^{-6} C^{-1}$
L° = initial length
ΔT = change in temperature

ΔL = $12x10^{-6}$ x 12 x (50-16) = 0.005 m

3 0

4 years ago

A planet orbits a star along an elliptical path from point X to point Y, as shown in the figure. In which of the following syste

8090 [49]

Answer:

The correct answer is Option D, the closed system containing the planet and the star.

Explanation:

To start, we need to define mechanical energy: the energy an object has from its motion and position.

The fundamental principle in physics is that the total energy in a closed system stays constant, even if it transforms. By saying "closed system," we refer to a system isolated from its surroundings. Energy never leaves the system; it only moves from one part to another.

This statement only applies to closed systems, however. An open system that interacts with its environment works differently. Energy may enter and leave the system through interaction with external forces, and this includes mechanical energy. For this reason, Option A and Option B are incorrect.

The remaining two options, C and D, only vary with the objects in the closed system. Option D includes the star; Option C does not.

However, we should take a closer look at Option C. Can an object have potential energy with itself? No, it cannot. It only has potential energy with other bodies. If the system is defined as the planet only, the only type of energy present is kinetic energy. We know a planet orbiting a star has more kinetic energy near and more gravitational potential energy further from its star. Thus it has less kinetic energy further from its star and less mechanical energy. Because of this, Option C is incorrect.

The only answer left is Option D. If we define the planet and star as a closed system, we find no net external force acting on it. Consequently, it obeys the law of conservation of energy. From prior reasoning, we know mechanical energy includes potential energy and kinetic energy and that the amounts of these energies vary with its orbit. As a result, mechanical energy is always conserved and always the same. In the end, the correct answer is Option D.

4 0

3 years ago