Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
5/8x? =2 1/2
And
5/8 - 2 1/2 =?
The answer would be those 2 can you plz park this a bran list
The polynomial <span>3x2y2 − 5xy2 − 3x2y2 + 2x2 can be simplified by combining like terms.
The result is:
-5xy2 + 2x2
The polynomial is
a binomial (2 terms),
the degrees is 3
the highest order in x is 2 and the highest order in y is 2.</span>
Answer:
The roots of a quadratic equation simply tell what values of x will make the equation true. A quadratic function is a function where the largest power for the variable is 2. ... A quadratic equation is given to you so that you can solve it for the variable. A quadratic function is given to you so that you can graph it.
Answer:
150 miles
Step-by-step explanation:
In this problem, we are only interested in the distance that Lauren drove, this means that her average speed (75 mph to the cost, and 25 mph on the way back) does not matter since the distance remains the same. If one leg of trip is 75 miles long, the total mileage for the round trip is:

Lauren drove 150 miles.