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Scorpion4ik [409]

4 years ago

9

A student weighs a container and then adds air. When the student weighs the container again the weight will be: a.less b.more th

an c.the same

2 answers:

maxonik [38]4 years ago

7 0

ZA student weighs a container and then adds air. When the students weighs the container again the weight will be C. The same.

Andru [333]4 years ago

3 0

Wouldn't air already be in the container, and if it isn't, then it would be heavier, since your adding something. Even if it is light as air, there would be <em>some</em> kind of difference.

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N2 (g) + 3 H2 (g) → 2 NH3 (g)

shusha [124]

This problem is asking for the rate of disappearance of gaseous nitrogen, given the rate of appearance of ammonia and the chemical reaction. At the end, the result turns out to be -0.228 M/s.

<h3>Rates of appearance and disappearance</h3>

In chemical kinetics, one of the most relevant calculations are based on rates of appearance and disappearance of chemical species in a chemical reaction. This can be calculated via rate portions based on the stoichiometric coefficients in the reaction.

Thus, for this problem, one can write:

$\frac{r_{N_2}}{-1} =\frac{r_{H_2}}{-3} =\frac{r_{NH_3}}{2}$

Where the rate of appearance or disappearance is divided by the stoichiometric coefficient. Therefore, one can solve for the rate of disappearance of N2 with:

$\frac{r_{N_2}}{-1} =\frac{r_{NH_3}}{2}\\\\r_{N_2}=\frac{r_{NH_3}*-1}{2}\\\\r_{N_2}=\frac{0.456M/s*-1}{2}\\\\r_{N_2}=-0.228M/s$

Learn more about chemical kinetics: brainly.com/question/26351746

3 0

2 years ago

You have a 1.212 M stock aqueous solution of Sr(OH)2. What volume of thestock solution (in mL) must be diluted with water to pre

Olin [163]

<u>Answer:</u> The volume of stock solution of strontium hydroxide needed is 4.125 mL

<u>Explanation:</u>

1 mole of $Sr(OH)_2$ produces 1 mole of strontium ions and 2 moles of hydroxide ions

Molarity of diluted strontium hydroxide solution = $\frac{0.200}{2}=0.100M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated strontium hydroxide solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted strontium hydroxide solution

We are given:

$M_1=1.212M\\V_1=?mL\\M_2=0.100M\\V_2=50mL$

Putting values in above equation, we get:

$1.212\times V_1=0.100\times 50\\\\V_1=\frac{0.1\times 50}{1.212}=4.125mL$

Hence, the volume of stock solution of strontium hydroxide needed is 4.125 mL

4 0

3 years ago

Electron configuration of vanadium-52

Aneli [31]

Answer:

[Ar]4s23d3

Explanation:

7 0

3 years ago

Given that H2 (g) + F2 (g) ⟶ 2HF (g) ΔH ∘ rxn = − 546.6 kJ 2H2 (g) + O2 (g) ⟶ 2H2O (l) ΔH∘rxn = − 571.6 kJ calculate the value o

BARSIC [14]

Answer : The value of $\Delta H_{rxn}$ for the reaction is, -521.6 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main reaction is,

$2F_2(g)+2H_2O(l)\rightarrow 4HF(g)+O_2(g)$ $\Delta H_{rxn}=?$

The intermediate balanced chemical reaction will be,

(1) $H_2(g)+F_2(g)\rightarrow 2HF(g)$ $\Delta H_1=-546.6kJ$

(2) $2H_2(g)+O_2(g)\rightarrow 2H_2O(l)$ $\Delta H_2=-571.6kJ$

Now we are multiplying reaction 1 by 2 and reversing reaction 2 and then adding all the equations, we get :

(1) $2H_2(g)+2F_2(g)\rightarrow 4HF(g)$ $\Delta H_1=2\times (-546.6kJ)=-1093.2kJ$

(2) $2H_2O(l)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_2=571.6kJ$

The expression for enthalpy of change will be,

$\Delta H=\Delta H_1+\Delta H_2$

$\Delta H=(-1093.2kJ)+(571.6kJ)$

$\Delta H=-521.6kJ$

Thus, the value of $\Delta H_{rxn}$ for the reaction is, -521.6 kJ

8 0

3 years ago

if a new substance forms during a chemical reaction but is dissolved in solution what symbol should follow the chemical formula?

trapecia [35]

The correct answer is D.(aq)

aq stands for aqueous, which is a solid that completely dissolves in a solution.

5 0

4 years ago

Read 2 more answers