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Annette [7]
3 years ago
9

The element that can act like a metal when it is under tremendous pressure and is probably responsible for Jupiter and Saturn's

magnetism is:__________. 1. hydrogen 2. water 3. helium 4. unobtanium 5. gold
Chemistry
1 answer:
erastova [34]3 years ago
3 0

Answer:

1. Hydrogen

Explanation:

These planets contain liquid hydrogen in their interior, while the earth has liquid iron in it.

When liquid hydrogen is in tremendous pressure enviroments, the electrons  that make up each atom of this element end up "jumping" to other atoms. These "jumps" allow liquid hydrogen to behave like a metal.

In addition, with the constant energy released by the nucleus of planets like Jupiter and Saturn, as well as their rotations, the liquid hydrogen receives induction of currents, giving rise to extremely powerful magnetic fields.

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. An atom of nitrogen has an atomic
GrogVix [38]

Here's the Answer !

Atomic number = no. of electrons = no. of protons, therefore :

  • no. of electrons = 7

  • no. of protons = 7

and mass number = no. of protons + no. of neutrons

so,

  • 7 + no. of neutrons = 14

  • no. of neutrons = 7
5 0
3 years ago
What element in the second period has the largest atomic radius?
madreJ [45]

Answer:

b. lithium

Explanation:

furthest to the left in second period

3 0
4 years ago
Round to the nearest whole number of 99.59
Luden [163]
Answer is 100.00!!!
8 0
3 years ago
Will GIVE BRAINLIEST --A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water. Answe
leva [86]

Answer:

0.5188 M or 0.5188 mol/L

Explanation:

Concentration is calculated as <u>molarity</u>, which is the number of moles per litre.

***Molarity is represented by either "M" or "c" depending on your teacher. I will use "c".

The formula for molarity is:

c = \frac{n}{V}

n = moles (unit mol)

V = volume (unit L)

<u>Find the molar mass (M) of potassium hydroxide.</u>

M_{KOH} = \frac{39.098 g}{mol}+\frac{16.000 g}{mol}+\frac{1.008 g}{mol}

M_{KOH} = 56.106 \frac{g}{mol}

<u>Calculate the moles of potassium hydroxide.</u>

n_{KOH} = \frac{14.555 g}{1}*\frac{1mol}{56.106g}

n_{KOH} = 0.25941(9)mol

Carry one insignificant figure (shown in brackets).

<u>Convert the volume of water to litres.</u>

V = \frac{500.0mL}{1}*\frac{1L}{1000mL}

V = 0.5000L

Here, carrying an insignificant figure doesn't change the value.

<u>Calculate the concentration.</u>

c = \frac{n}{V}

c = \frac{0.25941(9)mol}{0.5000 L}              

c = 0.5188(3) \frac{mol}{L}         <= Keep an insignificant figure for rounding

c = 0.5188 \frac{mol}{L}              <= Rounded up

c = 0.5188M               <= You use the unit "M" instead of "mol/L"

The concentration of this standard solution is 0.5188 M.

7 0
3 years ago
What volume (L) will 3.56 mol NH3 occupy at STP. (1 point)
mart [117]

Answer:

B

Explanation:

I hope it helps you good luck

7 0
3 years ago
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