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Annette [7]
3 years ago
9

The element that can act like a metal when it is under tremendous pressure and is probably responsible for Jupiter and Saturn's

magnetism is:__________. 1. hydrogen 2. water 3. helium 4. unobtanium 5. gold
Chemistry
1 answer:
erastova [34]3 years ago
3 0

Answer:

1. Hydrogen

Explanation:

These planets contain liquid hydrogen in their interior, while the earth has liquid iron in it.

When liquid hydrogen is in tremendous pressure enviroments, the electrons  that make up each atom of this element end up "jumping" to other atoms. These "jumps" allow liquid hydrogen to behave like a metal.

In addition, with the constant energy released by the nucleus of planets like Jupiter and Saturn, as well as their rotations, the liquid hydrogen receives induction of currents, giving rise to extremely powerful magnetic fields.

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A quantity of N2 gas originally held at 5.23 atm pressure in a 1.20 −L container at 26 ∘C is transferred to a 14.5 −L container
lara31 [8.8K]

Answer:

n (N₂) =  0.256 mol

n (O₂) = 1.0848 mol

n (Total) = 1.3408 mol

Pressure in new Container =  2.222 atm

Explanation:

Data Given:

For Nitrogen gas (N₂)

Pressure of N₂ gas =  5.23 atm

Volume of N₂ gas = 1.20 L

Temperature of N₂ gas = 26° C

Temperature of N₂ gas in Kelven (K) = 26° C +273

Temperature of N₂ gas in Kelven (K) = 299K

ideal gas Constant R = 0.08206 L atm K⁻¹ mol⁻¹

quantity of gas N₂ gas = ?

For Oxygen gas (O₂)

Pressure of O₂ gas =  5.21 atm

Volume of O₂ gas = 5.21 L

Temperature of O₂ gas = 26° C

Temperature of O₂ gas in Kelven (K) = 26° C +273

Temperature of O₂ gas in Kelven (K) = 299K

ideal gas Constant R = 0.08206 L atm K⁻¹ mol⁻¹

quantity of gas O₂ gas = ?

*we also have to find the total Pressure in the new container = ?

Formula Used

                         PV =nRT

                        n (N₂) = PV /RT . . . . . . . . . . . . . (1)

* Find the quantity of N₂

Put value in formula (1)

                n (N₂) = 5.23 atm x 1.20 L / 0.08206 L atm K⁻¹ mol⁻¹ x 299K

                n (N₂) =  6.276 atm .L /  24.52 L atm. mol⁻¹ x 299K

                n (N₂) =  0.256 mol

* Find the quantity of O₂

Put value in formula (1)

                n (O₂) = 5.21 atm x 5.10 L / 0.08206 L atm K⁻¹ mol⁻¹ x 299K

                n (O₂) =  26.6 atm .L /  24.52 L atm. mol⁻¹

                n (O₂) = 1.0848 mol

*Now to find the Total Quantity of both gases

                n(Total) =  n (N₂) + n (O₂)

                 n (Total) = 0.256 mol + 1.0848 mol

                 n (Total) = 1.3408 mol

**To find the Total Pressure in the new Container

Data to calculate Total Pressure in new container

Volume of gas = 14.5 L

Temperature of gases = 20° C

Temperature of gases in Kelven (K) = 20° C +273

Temperature of gases in Kelven (K) = 293K

ideal gas Constant R = 0.08206 L atm K⁻¹ mol⁻¹

Volume Pressure in new container = ?

Formula Used

                         PV =nRT

                        P = nRT / V . . . . . . . . . . . . . (2)

Put values in Equation (2)

           P =  1.3408 mol x 0.08206 L atm K⁻¹ mol⁻¹ x 293 K / 14.5 L

           P =  2.222 atm

8 0
3 years ago
In a chromatography experiment, chlorophyll pigments are separated using paper. What is the stationary phase in this experiment?
stira [4]
The correct answer is paper

7 0
3 years ago
Mendeleev created the first periodic table by arranging the elements in the order of ?
Maslowich
Mendleev arranged his periodic table in order of Atomic Mass...
4 0
3 years ago
List four greenhouse gases in the atmosphere. For each gas, describe its prevalence in the atmosphere, its natural sources, its
lukranit [14]

Answer:

Fossil fuels, carbon dioxide, gases released from polluted waste, and gases released in the air that are trapped in our atmosphere

Explanation:

5 0
3 years ago
6. How many atoms are there in .250 moles of lead?
strojnjashka [21]

Answer:

<h2>1.505 × 10²³ atoms </h2>

Explanation:

The number of atoms can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.250 × 6.02 × 10²³

We have the final answer as

<h3>1.505 × 10²³ atoms </h3>

Hope this helps you

3 0
2 years ago
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