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12345 [234]
2 years ago
6

N2 (g) + 3 H2 (g) → 2 NH3 (g)

Chemistry
1 answer:
shusha [124]2 years ago
3 0

This problem is asking for the rate of disappearance of gaseous nitrogen, given the rate of appearance of ammonia and the chemical reaction. At the end, the result turns out to be -0.228 M/s.

<h3>Rates of appearance and disappearance</h3>

In chemical kinetics, one of the most relevant calculations are based on rates of appearance and disappearance of chemical species in a chemical reaction. This can be calculated via rate portions based on the stoichiometric coefficients in the reaction.

Thus, for this problem, one can write:

\frac{r_{N_2}}{-1} =\frac{r_{H_2}}{-3} =\frac{r_{NH_3}}{2}

Where the rate of appearance or disappearance is divided by the stoichiometric coefficient. Therefore, one can solve for the rate of disappearance of N2 with:

\frac{r_{N_2}}{-1} =\frac{r_{NH_3}}{2}\\\\r_{N_2}=\frac{r_{NH_3}*-1}{2}\\\\r_{N_2}=\frac{0.456M/s*-1}{2}\\\\r_{N_2}=-0.228M/s

Learn more about chemical kinetics: brainly.com/question/26351746

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A gas occupies 100.0 mL at a pressure of 780 mm ahh. What is the volume of the gas when it’s pressure is increased to 880 mm Hg
vlabodo [156]
Hello!

The volume of the gas when its pressure is increased to 880 mm Hg is 88,64 mL

This question can be easily answered using the Boyle's Law, which states that as pressure increases, the volume is lower. It can be expressed in a mathematical way as follows:

P_1*V_1=P_2*V_2

So, from this equation we can clear V₂ to find the volume at 880 mm Hg:

V_2= \frac{P_1*V_1}{P_2}= \frac{780 mmHg*100 mL}{880 mmHg}=88,64 mL

Have a nice day!

4 0
4 years ago
Draw a Lewis structure for H2O that obeys the octet rule if possible and answer the following questions based on your drawing. 1
Nataliya [291]

This is an incomplete question, here is a complete question.

Draw a Lewis structure for H₂O that obeys the octet rule if possible and answer the following questions based on your drawing.

For the central oxygen atom:

The number of lone pairs =

The number of single bonds =

The number of double bonds =

Answer : The Lewis structure for H₂O is shown below.

For the central oxygen atom:

The number of lone pairs = 4

The number of single bonds = 2

The number of double bonds = 0

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The representation of valence electrons of an atom by dots around the symbol of an element is said to be the Lewis-dot symbol.

In the representation of Lewis-symbol, one electron dot must put on each side of the element symbol then paired the electrons.

The given molecule is, H_2O

As we know that hydrogen has '1' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in H_2O = 2(1) + 6 = 8

According to Lewis-dot structure, there are 4 number of bonding electrons and 4 number of non-bonding electrons.

For the central oxygen atom:

The number of lone pairs = 4

The number of single bonds = 2

The number of double bonds = 0

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It decreases in volume, as the energy is lost.
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Explanation:

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