Number 15 is no solution.
Number 27 is that x has to be between -2 or 2.
This could be explained as -2≤x≤2
<u>Given</u>:
Secants S V and T V intersect at point V outside of the circle. Secant S V intersects the circle at point W. Secant T V intersects the circle at point U.
The length of TU is (y - 2).
The length of UV is 8.
The length of SW is (y + 4)
The length of WV is 6.
We need to determine the length of line segment SV.
<u>Value of y:</u>
The value of y can be determined using the intersecting secant theorem.
Applying, the theorem, we get;

Substituting the values, we have;






Thus, the value of y is 6.
<u>Length of SV:</u>
The length of SV is given by




Thus, the length of SV is 16 units.
Hence, Option D is the correct answer.
Here, both numbers are divisible by 7 so that brings you to 9:4
Answer:
This will explain it
Step-by-step explanation:
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
The graph does not represent a function. When x=2, there are two different outputs, meaning it cannot be a function.