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3 years ago

3x^4-6x^3-32x^2+35x-12=0

Mathematics

1 answer:

Murljashka [212]3 years ago

4 0

This is a hard one
just try to factor out the same numbers

I used my calculator and got (x-4)(x+3)(3x^3-3x+1)

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Find the interest due on $600 at 9.5% for 120 days.

KATRIN_1 [288]

Answer:

Interest= $ 18.73

Step-by-step explanation:

Given : $600 at 9.5% for 120 days

To find : Find the interest due

Solution :

Simple interest formula $I=P\times r\times t$

Principle(P)=$600 , rate(r)=9.5%=0.095 , time (t)= 120 days

In years, 1 year = 365 days

1 day = $\frac{1}{365}$ year

120 days = $\frac{120}{365}$ year

Put values in the formula

$I=P\times r\times t$

$I=600\times 0.095\times\frac{120}{365}$

$I=\frac{6840}{365}=18.73$

Therefore, Interest= $ 18.73

5 0

3 years ago

Read 2 more answers

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

How was basic math used

dmitriy555 [2]

It was used to see how your basic math skills

4 0

3 years ago

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In the image, shape ABCD is similar to shape WXYZ. Find the measure of side ZW.

vladimir2022 [97]

Solution:

we are given that

In the image, shape ABCD is similar to shape WXYZ.

we have been asked to find the measure of side ZW.

As we know that when two shapes are similar then the ratios of their corresponding sides are equal.

So we can write

$\frac{zw}{6}= \frac{18}{24}\\
\\
ZW=6*\frac{18}{24}\\
\\
ZW=\frac{18}{4}\\
\\
ZW=4.5\\$

Hence ZW=4.5 Inches.

6 0

3 years ago

Please, provide an explanation and answer

Helen [10]

Answer:

whats the question

Step-by-step explanation:

4 0

3 years ago

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