What are the zeros of (3x−2)(x+4)

The product of 2x^3 and 6x^5 is

Butoxors [25]

12x^8 multiply the leading terms (2and 6) then add exponents (5and3)

3 0

2 years ago

Fill in the blank.

Marrrta [24]

Question:

Fill in the blank.

23 x 6 = (20 + 3) * 6

23 x 6 = _ + (3x6)

Options

20 * 6

20 * 3

20 * 5

Answer:

20 * 6

Step-by-step explanation:

Given

Expression 1: 23 * 6 = (20 + 3) * 6

Expression 2: 23 * 6 = __ + (3 * 6)

Required

Fill in the blank

From Expression 1

23 * 6 = (20 + 3)*6

Using Distributive Property; The expression becomes

23 * 6 = 20 * 6 + 3 * 6

23 * 6 = (20 * 6) + (3 * 6)

By Comparing this with expression 2

23 * 6 = __ + (3 * 6)

The blank position is occupied by 20 * 6.

Hence, the correct option that fills the missing blank correctly is 20 * 6

7 0

2 years ago

Igneous rock that cools slowly will have what type of mineral grains??

daser333 [38]

I think it would have crystal formations if I remember correctly.

7 0

2 years ago

Dakota is saving money to buy a new ferret cage.In the the first week she saved $24 each week she saves $6 how much money will S

MissTica

$24 x 6 = 144 Minus the $6 she spent per week -$36 = $108

I guess that is what you meant when you typed "she saved $24 each week she saves $6???

3 0

3 years ago

Read 2 more answers

The following prices, in dollars, of 7.5-cubic-foot refrigerators were recorded from a random sample. 314 305 344 283 285 310 3

Mariana [72]

Answer:

$t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109$

The degrees of freedom are given by:

$df=n-1=10-1=9$

And the p value would be given by:

$p_v =P(t_{9}>1.109)=0.148$

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

Step-by-step explanation:

Information given

314 305 344 283 285 310 383 285 300 300

We can calculate the sample mean and deviation with the following formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}$

$\bar X=310.9$ represent the sample mean

$s=31.09$ represent the standard deviation for the sample

$n=10$ sample size

$\mu_o =300$ represent the value to test

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to verify if the true mean is greater than 300, the system of hypothesis would be:

Null hypothesis: $\mu \leq 300$

Alternative hypothesis: $\mu > 300$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109$

The degrees of freedom are given by:

$df=n-1=10-1=9$

And the p value would be given by:

$p_v =P(t_{9}>1.109)=0.148$

Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

6 0

3 years ago