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VikaD [51]
3 years ago
12

The triangles below are similar.Which similarity statement expresses the relationship between the two triangles?

Mathematics
1 answer:
a_sh-v [17]3 years ago
7 0

Answer:

FGH ~ KLJ

Step-by-step explanation:

You have to write the similarities in order. Meaning, each letter of the triangle must correspond with each letter of the other triangle, in order. So if ABC is similar to LMN, then A must be similar to L, B must be similar to M, and C must be similar to N.

So,F = 91 and K = 91. They are the first part of the similarity. Then, G and L both equal 65, so they are the second part. Finally, H and J both equal 24, so they must be the third part.

Therefore,  FGH ~ KLJ.

(If you are wondering about the second part: " ≅ " means congruent to and " ~ " means similarity so the ~ symbol is the right one.)

I hope this helps! Good Luck!

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HELP! WILL AWARD BRAINLIEST TO WHOEVER ANSWERS BOTH PARTS CORRECTLY!!
rewona [7]

check the picture below.

now, we're assuming the trapezoid is an isosceles trapezoid, namely AD = BC, and therefore the triangles are twins.

incidentally, b is the height of the trapezoid and likewise is also the altitude or height of the concrete triangle.

so we can simply get the area o the trapezoid, notice the bottom base is a+185+a, and then get the area of the concrete triangle and subtract the triangle from the trapezoid, what's leftover is just the vegetation area.

\bf \begin{cases} a=283\cdot cos(80^o)\\ a\approx 49.14\\ --------\\ b=283\cdot sin(80^o)\\ b\approx 278.70 \end{cases}\\\\ -------------------------------\\\\ \textit{area of a trapezoid}\\\\ A=\cfrac{h(x+y)}{2}~~ \begin{cases} x,y=\stackrel{bases}{parallel~sides}\\ h=height\\ ----------\\ x=185\\ y\approx \stackrel{a+185+a}{283.28}\\ h\approx\stackrel{b}{278.70} \end{cases} \\\\\\ A=\cfrac{278.70(185+283.28)}{2}\implies A\approx 65254.818

so that's the area of the trapezoid, now let's get the area of the triangle.

\bf \stackrel{triangle}{\cfrac{1}{2}(185)(b)}\implies \cfrac{1}{2}(185)(278.70)\qquad \approx 25779.80\\\\ -------------------------------\\\\ \stackrel{\textit{area for vegetation}}{\stackrel{\textit{area of trapezoid}}{65254.818}~~-~~\stackrel{\textit{area of triangle}}{25779.80}}\implies 39475.018

since we know 36 yd² cost 12 bucks, then how much will it be for 39475.018 yd²?

\bf \begin{array}{ccll} yd^2&\$\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 36&12\\ 39475.018&x \end{array}\implies \cfrac{36}{39475.018}=\cfrac{12}{x}\implies x=\cfrac{39475.018\cdot 12}{36} \\\\\\ x\approx 13158.339\overline{3}

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<u>Step-by-step explanation:</u>

A: the center of the circle

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C: the radius of the circle

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<em />

Circles are named by their center, so this is named "Circle A".

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the. if you have a production of around 10 you will get 7.

or you can do.

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