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2 years ago

13 divided by 1209 please help

1 answer:

5 0

The answer is 93 It’s 1209 divided by 13 not 13 divide by 1209 ;) hope this helps ! Because when we’re dividing the number get smaller and when we multiplying the number gets bigger , have a nice day !

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Help me please please please

morpeh [17]

Answer:

Step-by-step explanation:

let coordinates of D are (x,y)

mid point of AC=midpoint of BD

so{ (-3+4)/2,(1+6)/2}={(x+(-1))/2,(y+4)/2}

(1/2,7/2)={(x-1)/2,(y+4)/2}

(x-1)/2=1/2

x-1=1

x=1+1=2

(y+4)/2=7/2

y+4=7

y=7-4=3

so D is (2,3)

4 0

3 years ago

Can you Increase £40 by 20%

Nady [450]

£40 by 20% = 40 * 0.2 = 8
So 40 + 8 = 48

<span>Increase £40 by 20% is 48</span>

4 0

3 years ago

Read 2 more answers

List all the factors of 16

Olenka [21]

Answer:

There are 5 factors of 16, which are 1, 2, 4, 8, and 16.

5 0

3 years ago

Read 2 more answers

A random variable X is uniformly distributed over the interval (48, 96).

Katen [24]

Answer:

a) $P(50 < X$

b) $P(X$

c) $P(X>90)=1- \frac{90-48}{48} = 1-0.875 = 0.125$

d) $P(X$

And using the CDF we got:

$P(X$

$P(X>80)$

And using the CDF and the complement rule we got:

$P(X>80)=1- \frac{80-48}{48} = 1-0.667 = 0.333$

So then the probability required would be:

P(X < 60 or X > 80) = 0.25+0.333= 0.583

Step-by-step explanation:

For this case we define the random variable of interest X, and we know the distribution given by:

$X \sim Unif (a= 48, b=96)$

The density function is given by:

$f(x) = \frac{1}{96-48} = \frac{1}{48} , 48 \leq X \leq 96$

And the cumulative distribution function is given by:

$F(x) = \frac{x-48}{96-48} , 48 \leq X \leq 96$

Part a

We want this probability:

$P(50 < X$

And we can find this probability with this difference:

$P(50 < X$

And replacing we got:

$P(50 < X$

Part b

We want this probability:

$P(X$

And using the CDF we got:

$P(X$

Part c

We want this probability:

$P(X>90)$

And using the CDF and the complement rule we got:

$P(X>90)=1- \frac{90-48}{48} = 1-0.875 = 0.125$

Part d

$P(X$

And using the CDF we got:

$P(X$

$P(X>80)$

And using the CDF and the complement rule we got:

$P(X>80)=1- \frac{80-48}{48} = 1-0.667 = 0.333$

So then the probability required would be:

P(X < 60 or X > 80) = 0.25+0.333= 0.583

8 0

4 years ago

The volume of a box is given by V = 2x3-11x2 +10x +8. One side is (x - 4) and another side is (2x + 1).

user100 [1]

Answer:

The length of the third side is ( x - 2 )

Step-by-step explanation:

Volume of a box is the product of its length, width and height.

Volume of box = length × width × height.

One side is (x - 4) and another side is (2x + 1).

These given sides can be either length, height or width.

The volume of a box is given by V = 2x3-11x2 +10x +8. This means each of the sides are factors of the volume. To get the third side, we divide the volume by the product of the two given sides.

Product of the two given sides =

( x-4 ) (2x + 1) = 2x^2 + x - 8x + 4

= 2x^2 - 7x - 4

The long division is shown on the attached photo

The length of the third side is ( x - 2 )

4 0

3 years ago

Read 2 more answers