In analytical geometry, there are already derived equations to find the distance of lines and points as well as the angle made between two lines. As special case is when the other line is one of the coordinate axis. Then, the formula can be simplified to
tan θ =m, where m is the slope of the equation
In the next step, we also incorporate operations of calculus. Since the slope is equal to Δy/Δx, this is equivalent to dy/dx in calculus. Therefore, you can find the slope by differentiating the equation in terms of x.
<span>y-2x=7
y = 2x+7
dy/dx = 2 =m
So,
tan </span>θ = 2
θ = tan⁻¹(2)
θ = 63.43°
This is a right angle triangle.
So, by Pythagoras theorem,
√(32^2+20^2) = x
or √(1024+400) = x
or √1424 = x
or <em>37.74 = x</em>
Answer:
0.25
Step-by-step explanation:
density= m/v
density= 25/100
density=.25
Answer:
42300000
Step-by-step explanation:
Use known fact
Consider 1 square kilometer:
So, to find the answer, you have to multiply given number of square kilometers by 1000000:
Answer:
Jacqueline runs at 6.25 minutes per mile
Step-by-step explanation:
Here we have that the total training time for Jacqueline = 54 minutes
The time for which Jacqueline swims = 30 minutes
Therefore, the time in which Jacqueline runs = 54 min. - 30 min. = 20 minutes
Therefore the equation for Jacqueline's speed = Distance/Time we have
Jacqueline's pace = 3.2 miles/20 minutes = 0.16 miles/minute
Therefore Jacqueline's pace = 0.16 miles/minute
The equation for Jacqueline's pace in miles/minute is presented as follows
Jacqueline's pace in miles/minute = Time of running/Distance
Jacqueline's pace in miles/minute = 1/0.16 miles/minute = 6.25 minutes/mile.
