So k in the first problem would =1/2
and i guess in the second problem just put k in place of the first space and in the second space put 8 for x. y would then =4. Idk if I did this right, though, I'm honestly a little confused too.
This is a ratio problem; the ratio of the length to width is constant (and therefore equal):
4 /6 = 15 / x
Now, with a ratio, we may do any allowable algebra operation: cross-multiply, invert both sides, multiply or divide both sides by the same amount, etc.
Let's cross-multiply:
4x = (15)(6)
x = 90/4
x = 22.5 in.
1 pencil + 1 eraser = $1.10
Pencil cost $1 more than the eraser.
⇒ If we take away $1 from the total, both the pencil and the eraser will cost the same.
⇒ $1.10 - $1.00 = $0.10
Divide by 2 to find the cost of the eraser.
⇒$0.10 ÷ 2 = $0.05
Find the cost of the pencil, which is $1 more than the eraser.
⇒ $0.05 + $1 = $1.05
Answer: The eraser costs $0.05
Answer:
40
Step-by-step explanation:
Sums:
1, 3
2, 2
4, 0
31 and 22 are to small of numbers. That leaves 40.
40 and 04
so 40
- 04
____
= 36
Good luck,
Camryn :)
