All categories

3 years ago

Grade 7. Mathematics: Integers.

Mathematics

1 answer:

USPshnik [31]3 years ago

8 0

B.= -12. c.=-4 ....I'm doing this type of stuff too right now

You might be interested in

I need help ASAP please giving brainliest

vlabodo [156]

Answer:

Step-by-step explanation:

A and B form a right angle

meaning that A+B=90

if A=58

B=90-58 = 32

answers

B is acute angle, true

second statement is False

Last statement is true

6 0

3 years ago

Help with geometry!!!!!!!

Black_prince [1.1K]

Since the angle under angle 3 is a right angle (because of the little orange square) we can assume that angle 3 plus angle 2 equals 90 degrees. so
(2x - 5) + (4x - 13) = 90
6x - 18 = 90
6x = 108
x = 18
measure of angle 2 = 36 - 5 = 31
measure of angle 3 = 72-13 = 59

6 0

3 years ago

Read 2 more answers

5. F-LE.1.2

telo118 [61]

Answer:

A, an = 2n. B. an = 2(n-

Step-by-step explanation:

can you brainlist me

8 0

2 years ago

If mike read 30 pages an hour how long will it take him to read 1225 pages

Gnesinka [82]

Answer: 2450 min or 40hr and 50 min

Step-by-step explanation:

We can use a proportion to set up this equation.

$\frac{30 pages}{60 min} =\frac{1225 pages}{x min}$

We cross muliply so get our equation.

$30x=1225(60)\\$

$30x=73500$

$x=2450 min$

It took Mike 2450 min to read 1225 pages. We can also use a proportion to write this in hours

$\frac{60min}{1hr} =\frac{2450min}{x }$

$60x=2450$

$x=40 hr 50 min$

5 0

3 years ago

Average rate of change from G from x=3 to x=4 is

e-lub [12.9K]

For a function of $f$ , the average rate of change can be found as follows:

$ARC=\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}}$

So, we only need two points to compute this value. So, in this problem we have a table with several points, but the problem establishes that the ARC we need to find is the one between two points, that is, when x=3 and x=4. In this problem, $g$ is the function, so:

$ARC=\frac{g(x_{2})-g(x_{1})}{x_{2}-x_{1}}\\ \\ ARC=\frac{9-8}{4-3} \\ \\ \therefore \boxed{ARC=1}$

4 0

3 years ago