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Anna007 [38]
3 years ago
15

What is 8x-4y=-12;-3,-1,1 solve for y

Mathematics
1 answer:
polet [3.4K]3 years ago
3 0
8x - 4y = -12
4y = 8x + 12
y = 8/4 x + 12/4
y = 2x + 3

When x = -3,
y = 2(-3) + 3 = -6 + 3 = -3
When x = -1,
y = 2(-1) + 3 = -2 + 3 = 1
When x = 1,
y = 2(1) + 3 = 2 + 3 = 5
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Write each whole number in expanded form.
Phantasy [73]
A) 200,000 + 40,000 + 4,000 + 300 + 6

b) 70,000,000 + 7,000,000 + 70,000+ 9,000 + 100 + 1
4 0
3 years ago
Pls help
Juli2301 [7.4K]

Answer:

I believe the answer is 540* because

Step-by-step explanation:

we start with the fractions, we have 3/4 and 1/4 which makes a whole, to make it easier i added that to 329 to get 330. Then i added 330 to 210 to get 540.

4 0
3 years ago
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on Tuesday pierce ran 3/4 mile and walked 3/4 on Wednesday he ran 2/4 mile and walk 1 1/4 miles hiw much farther did pierce run
Korvikt [17]

Answer:

On Tuesday

3/4 + 3/4 = 3/2 = 1 1/2 = 1.5

On Wednesday

2/4 + 1 1/4 = 7/4 = 1 3/4 = 1.75

Then we subtract

1.75 - 1.5 = 0.25


6 0
3 years ago
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two pumps of different sizes, working together, can empty a fuel tank in 3 hours. the larger pump can empty the tank in 4 hours
bonufazy [111]
Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour. 


8 0
3 years ago
Read 2 more answers
What is the area of the figure shown?
musickatia [10]

Check the picture below.

now, we're making an assumption that, the two blue shaded region are equal in shape, and thus if that's so, that area above the 14 is 6 and below it is also 6, 14 + 6 + 6 = 26.

so hmm if we simply get the area of the trapezoid and subtract the area of the yellow triangle and the area of the cyan triangle, what's leftover is what we didn't subtract, namely the shaded region.

\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h~~=height\\ a,b=\stackrel{parallel~sides}{bases~\hfill }\\[-0.5em] \hrulefill\\ h=15\\ a=14\\ b=26 \end{cases}\implies A=\cfrac{15(14+26)}{2}\implies A=300 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Areas}}{\stackrel{trapezoid}{300}~~ - ~~\stackrel{yellow~triangle}{\cfrac{1}{2}(26)(9)}~~ - ~~\stackrel{cyan~triangle}{\cfrac{1}{2}(15)(6)}} \\\\\\ 300~~ - ~~117~~ - ~~45\implies 138\qquad \textit{blue shaded area}

8 0
2 years ago
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