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Vaselesa [24]
3 years ago
11

How can knowing the gcf and lcm help you when you add subtract and multiply fractions?

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
8 0

If the denominators are different numbers, it is necessary to find a common denominator. Find the Lowest Common Multiple (LCM) of the denominators (also known as the Lowest Common Denominator, or LCD) and convert the fractions to equivalent fractions with the same denominator. Now they have the same denominator, proceed as above.

Example: 1/4 + 1/6 = 3/12 + 2/12 = 5/12 (here LCM=12)

You don't have to do anything to fractions to multiply them, but you may need to reduce one after multiplying. To do that, find the GCF of the numerator and the denominator and divide both of them by it. If the GCF is 1, the fraction is in its simplest form.

Example: 1/4 · 2/5 = 1·2/4·5=2/20=1/10 (here GCF=2)

Maksim231197 [3]3 years ago
4 0
<span>In order to add and subtract fractions, we must be able to find a <u>common denominator</u>.
The LCD, or least common denominator, is the LCM of the denominators. Once we've added, subtracted or multiplied fractions, we often have to simplify the fraction.
In order to do this, we divide the numerator and denominator by their GCF. This means we must be able to find the LCM and GCF in order to work with fractions.</span>
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Which relations are functions?
pychu [463]

For a relation to be a function every x value will have a single y value.

The first one has two x values of -2 but their y values are different so can’t be a function.

The second one has two 10’s with different y values so isn’t a function.

The 3rd one has 1 and -1 with the same y value, so isn’t a function.

The correct answer is the 4th choice

5 0
3 years ago
The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
zalisa [80]

Answer: 272

Step-by-step explanation:

Let a1=11

a2=20

a3=29

Formula for sequence=

an=a1+(n-1)d

an = nth term

a1= first term

n= nth position

d= common difference

We are looking for the 30th term,so our n=30

d= a2-a1

d= 20-11

d= 9

Using the formula

an= a1+(n-1)d

a30= 11+(30-1)9

a30= 11+(29)9

a30= 11+(29×9)

a30= 11+261

a30= 272

Therefore, the 30th term is 272

8 0
3 years ago
An older person is 8 years older than seven times the age of a younger person. The sum of their ages is 32. What are their ages?
tatiyna

Answer:

there ages are 29 and 3 years old

3 0
2 years ago
Axis of sym: x =
marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
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it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

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let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

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the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

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factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

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Pavlova-9 [17]

Answer:

describe the relationship between what

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