For a relation to be a function every x value will have a single y value.
The first one has two x values of -2 but their y values are different so can’t be a function.
The second one has two 10’s with different y values so isn’t a function.
The 3rd one has 1 and -1 with the same y value, so isn’t a function.
The correct answer is the 4th choice
Answer: 272
Step-by-step explanation:
Let a1=11
a2=20
a3=29
Formula for sequence=
an=a1+(n-1)d
an = nth term
a1= first term
n= nth position
d= common difference
We are looking for the 30th term,so our n=30
d= a2-a1
d= 20-11
d= 9
Using the formula
an= a1+(n-1)d
a30= 11+(30-1)9
a30= 11+(29)9
a30= 11+(29×9)
a30= 11+261
a30= 272
Therefore, the 30th term is 272
Answer:
<h2>SEE BELOW</h2>
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>let's solve:</h3>
vertex:(h,k)
therefore
vertex:(-1,4)
axis of symmetry:x=h
therefore
axis of symmetry:x=-1
- to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0
vertex form of quadratic equation:
therefore
- y=a(x-(-1))²+4
- y=a(x+1)²+4
it's to notice that we don't know what a is
therefore we have to figure it out
the graph crosses y-asix at (0,3) coordinates
so,
3=a(0+1)²+4
simplify parentheses:

simplify exponent:

therefore

our vertex form of quadratic equation is
let's simplify it to standard form
simplify square:

simplify parentheses:

simplify addition:

therefore our answer is D)y=-x²-2x+3
the domain of the function

and the range of the function is

zeroes of the function:




factor out x and -1 respectively:

group:

therefore

Answer:
describe the relationship between what
Step-by-step explanation: